can literals used without variable in c?

Question

This question is little bit weird.

Just out of curiosity, is it possible to use the literals without variable assignment in C ?

Generally, we do like as follows,

#include<stdio.h>
int main()
{
 // Here we are using the literal '7' and assigning it to variable 'a'  which will hold it in some address space
 int a = 7;
 printf("Hello : %d\n",a);
 return 0;
}

So, is it possible to use the literals without variables ?

Thanks in advance.

don't you notice that you're using a literal without a variable assignment in the `return 0;` line? — Barmar, Jan 01 '14 at 06:47
Not to mention in the format string in the `printf()` statement... — Jonathan Leffler, Jan 01 '14 at 07:07

score 4 · Accepted Answer · answered Jan 01 '14 at 06:46

4

If you mean something like this:

printf("Hello : %d\n", 7);

then yes, it's fine.

answered Jan 01 '14 at 06:46

Barmar

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Thanks Barnar. It worked. Thanks for the quick response. :) – Dinesh Jan 01 '14 at 06:47

score 2 · Answer 2 · answered Jan 01 '14 at 06:48

2

Then you don't even need %d

printf("Hello : 7 \n");

answered Jan 01 '14 at 06:48

Digital_Reality

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score 0 · Answer 3 · answered Jan 01 '14 at 09:07

yes , they are used all the time , in return statements ,as constants etc . , even in your printf statement the %d is a placeholder for an int( or integer) , i.e. you can always replace a by 7 , however this approach of defining constants is favoured as if you will be using some number many times in your code , (ex. pi=3.14 in a math program) , its value needs to be edited at one place only and variable naming provides a easier reference system , and is hence more common practice .

can literals used without variable in c?

3 Answers3