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import argparse

parser = argparse.ArgumentParser(description='sort given numbers')
parser.add_argument('-s', nargs = '+', type = int)
args = parser.parse_args()
print(args)

On command line when I run the command

python3 file_name.py -s 9 8 76

It prints Namespace(s=[9, 8, 76]).

How can I access the list [9, 8, 76]? What is the namespace object. Where can I learn more about it?

Martijn Pieters
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Shashank Garg
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3 Answers3

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  • The documentation for argparse.Namespace can be found here.
  • You can access the s attribute by doing args.s.
  • If you'd like to access this as a dictionary, you can do vars(args), which means you can also do vars(args)['s']
Bill Lynch
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  • argparse.Namespace can also be used for type-hinting! i.e. args: argparse.Namespace. Your answer helped me figure out that it was a module specific Namespace type instead of global. – colby-ham Oct 23 '19 at 23:01
3

It is the result object that argparse returns; the items named are attributes:

print(args.s)

This is a very simple object, deliberately so. Your parsed arguments are attributes on this object (with the name determined by the long option, or if set, the dest argument).

Martijn Pieters
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  • Thanks a lot for the answer. Where can I know more about this namespace object? Where and how is it used? I couldn't find anything good on googling. – Shashank Garg Dec 29 '13 at 18:00
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    I linked you to the documentation in my answer already. There is not that much to say about it, really. – Martijn Pieters Dec 29 '13 at 19:29
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you can access as args.s , "NameSpace class is deliberately simple, just an object subclass with a readable string representation. If you prefer to have dict-like view of the attributes, you can use the standard Python idiom, vars()." Source

Owen
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Veaceslav Mindru
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