Uncaught TypeError: Object function () exception thrown in console.log

Question

Exception thrown on console. Why this exception is been thrown? After this exception is thrown, onchange dropdown does not work anymore. What can I do to prevent this from happening

Uncaught TypeError: Object function () {
    if (this instanceof String) {
        if (this.indexOf("%") != -1) {
            return this;
        }
    }
    return this + "px";
} has no method 'push'

Method in Javascript

Object.prototype.measurement = function() {
    if (this instanceof String) {
        if (this.indexOf("%") != -1) {
            return this;
        }
    }
    return this + "px";
};

Link to code

There's no mention of a `push` method being called in your code, so it's not possible to answer your question without the rest of the code. — Blender, Dec 23 '13 at 06:40
Careful: `'' instanceof String // false`. Use `typeof` instead. — elclanrs, Dec 23 '13 at 06:45
It's just a tip. String literals are not instances of the String constructor. — elclanrs, Dec 23 '13 at 06:49
@elclanrs Oh, there are no parent for string literals? How does the string methods work on them, then? — thefourtheye, Dec 23 '13 at 06:50
@thefourtheye: String literals are primitives, while a string instance `new String('asdasd')` is an object. See here http://stackoverflow.com/questions/17256182/javascript-string-literal-vs-string-object — elclanrs, Dec 23 '13 at 08:58

score 0 · Accepted Answer · edited Dec 23 '13 at 08:48

0

The problem was solved by changing function definition from

Object.prototype.measurement = function() {}

to

function measurement(position) {}

edited Dec 23 '13 at 08:48

Anto Jurković

11,188
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answered Dec 23 '13 at 08:39

java_dude

4,038
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Uncaught TypeError: Object function () exception thrown in console.log

1 Answers1