Checking string length with strlen

Question

I have this code, i want it to check if the length is NOT 32 or 40. The code below only checks if the word is 32 or 40 in length.

<?
$name = mysql_real_escape_string($_POST['dgt']);
$len = strlen($name);
if (!($len == "32" or $len == "40")){
print "This is not a name.";
} else {
echo 'This is a name';
?>

if checking an integer (as is the case in `strlen`) even in PHP, don't check `int` values against their `string` equivalents, technically this is a logic error as `"32"` is checking for the string value of '32' and NOT the integer value of 32 — txtechhelp, Dec 17 '13 at 08:58

score 4 · Accepted Answer · answered Dec 17 '13 at 08:53

4

if ($len != 32 && $len != 40)

try that out

answered Dec 17 '13 at 08:53

txtechhelp

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Why are you wrapping an integer in quotes? – Ryan Dec 17 '13 at 08:55
yeah, forgot to take off the quotes :) .. was going to mention not to check integers in quotes above :) .. thanks for the catch! – txtechhelp Dec 17 '13 at 08:56

score 0 · Answer 2 · answered Dec 17 '13 at 08:54

0

What about

if($len != 32 and $len != 40)

answered Dec 17 '13 at 08:54

Maarkoize

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It is a valid logical operator: http://www.php.net/manual/en/language.operators.logical.php – Maarkoize Dec 17 '13 at 08:55
@RUJordan - `and` is a valid conditional statement in PHP. So is `or`. – Ryan Dec 17 '13 at 08:56
You test string!? `int strlen ( string $string )` Test integer instead… – ChoiZ Dec 17 '13 at 08:56

score 0 · Answer 3 · answered Dec 17 '13 at 08:56

0

<?php
$name = mysql_real_escape_string($_POST['dgt']);
$len = strlen($name);
if ($len != 32 && $len != 40){
print "This is not a name.";
} else {
echo 'This is a name';
?>

answered Dec 17 '13 at 08:56

krutssss

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1
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Checking string length with strlen

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