JISON: why in regexp used "." instead of \.?

Question

[0-9]+("."[0-9]+)?\b  return 'NUMBER';

why in this regexp used "." instead of \. ?

I'm assuming the double quotes means "literal", so `"."` is what you would expect for `\.`. — Lasse V. Karlsen, Dec 15 '13 at 16:24
in normal regexp "." means "anything", what kind of regexp it is? — redexp, Dec 16 '13 at 16:38

score 2 · Accepted Answer · answered Dec 17 '13 at 15:23

2

Because that's a Jison grammar tokenization rule not an exact regex.
In Jison a token is surrounded in ".

In the compiled rules you can see the rule converted to a regex:

["[0-9]+(?:\\.[0-9]+)?\\b", "return 'NUMBER';"],

answered Dec 17 '13 at 15:23

rzymek

1

where I can read more about "Jison grammar tokenization rule"? – redexp Dec 17 '13 at 15:59

1 Answers1