Cutting string by first number found

Question

I have to cut the first part of my string before any number found. For example:

string: "BOBOSZ 27A lok.6" should be cutted to 'BOBOSZ "

string: "aaa 43543" should be cutted to "aaa "

string: "aa2bhs2" should be cutted to "aa"

Im trying with preg_split and explode funcionts but i can't get the right result for now.

Thanks in advance !

Why you don't have the space in the first and second string? — Casimir et Hippolyte, Dec 13 '13 at 00:47
Yep, you're right it should be cutted to 'BOBOSZ ' and 'aaa ', i will correct my question — Michal Olszowski, Dec 13 '13 at 00:49

Casimir et Hippolyte · Accepted Answer · 2013-12-13T00:57:45.090

1

You can use this pattern with the preg_match() function:

preg_match('/^[^0-9]+/', $str, $match);
print_r($match);

pattern details:

^         # anchor: start of the string
[^0-9]+   # negated character class: all that is not a digit one or more times

note: you can replace + by * if you consider that an empty string is a valid result.

If you absolutly want to use the preg_split() function, you do:

$result = preg_split('/(?=(?:[^0-9].*)?$)/s', $str);
echo $result[0];

edited Dec 13 '13 at 00:57

answered Dec 13 '13 at 00:49

After using $answer = preg_split('/^[^0-9]+/', $adress[0]); I got "array (size=2) 0 => string '' (length=0) 1 => string '27A lok.6' (length=9)" First string is empty and second string is the second part, but I need this first part... – Michal Olszowski Dec 13 '13 at 00:56
@69punk: refresh the page. – Casimir et Hippolyte Dec 13 '13 at 00:58
you're right, preg_match works better in this case. Thanks ;-) – Michal Olszowski Dec 13 '13 at 01:06

score 0 · Answer 2 · answered Dec 13 '13 at 01:12

0

preg_match('#(\w+)\s?\d+#', $string, $match);

You should get $match[1] as I remember :)

answered Dec 13 '13 at 01:12

Tassoman

2 Answers2