String formatting options

Question

I am porting a C code to xtend, and I have an 32bit integer. Since Java's Integer has a maximum value of 0x7FFFFFFF, I decided to use Long because I would need 0xFFFFFFFF.

When I print it out,

Long value = 0xFFFFFFFFFFFFFFFF;
String::Format("0x%08X", value);

I am getting the output: 0xFFFFFFFFFFFFFFFF. I am expecting to only get 0xFFFFFFFF. To get rid of the leading Fs, I tried doing this:

value.bitwiseAnd(0x00000000FFFFFFFF)

But the output is still the same. How can I format it in String::Format such that it will not display the the first FFFFFFFF? I only need the lower 32bits.

The string formatting code you've given isn't valid Java - are you actually writing Java or something else? — Jon Skeet, Dec 11 '13 at 07:27
And why are you setting the value to 0xFFFFFFFFFFFFFFFF when you only actually want 0xFFFFFFFF? — Jon Skeet, Dec 11 '13 at 08:03

score 1 · Accepted Answer · answered Dec 11 '13 at 07:59

1

Try this:

BigInteger in = new BigInteger("FFFFFFFFFFFFFFFF", 16);        
System.out.println(String.format("%.8s", String.format("%x", in)));

answered Dec 11 '13 at 07:59

Chandrayya G K

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String formatting options

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