Dynamic decimal places

Question

I was using the function number_format() to manage my decimal places, but I'm not getting the result I want. I wish to have up to 6 decimal places, but i don't want every number to display them. For example if my output is 27.54, number_format is gonna give me 27.540000. Is there function or a way to ignore those extra zeros and only display the significant decimals?? Thank you!

Take a look at this (possible duplicated): http://stackoverflow.com/a/5429945/722135 — Babblo, Dec 10 '13 at 03:46
rtrim doesn't work for me, since it erases the zeros of my integers... my 25000 turns 25... — inBlackAndWhite, Dec 10 '13 at 04:11

score 2 · Answer 1 · answered Dec 10 '13 at 03:48

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$r = 27.54;
 echo (float) number_format($r,6);

answered Dec 10 '13 at 03:48

Nouphal.M

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score 0 · Answer 2 · answered Dec 10 '13 at 03:45

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If I understand correct, you want up to 6 decimals, but no more and if its less that 6 decimal places to ignore any zeros. If so, just get the floatval of the formated string:

$number = floatval(number_format($number,6))

answered Dec 10 '13 at 03:45

this works great!! but only works when I'm dividing...when I'm multiplying I get 1.48 * 1000 = 1 .... – inBlackAndWhite Dec 10 '13 at 03:54

score 0 · Accepted Answer · answered Dec 10 '13 at 03:46

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Try using (float) to cast the value back to a float (which will remove the trailing 0's):

$val = number_format(11.11, 6);
echo (float)$val;

answered Dec 10 '13 at 03:46

Marty

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I dont know why, but if I use number_format it erases the zeros in my integers. the $val = (float) $val; doesn't let me limit the decimals, but works great removing the insignificant zeros!! Thank you!! – inBlackAndWhite Dec 10 '13 at 04:15

Dynamic decimal places

3 Answers3