How to replace 1 with first, 2 with second,3 with third etc

Question

Is there any inbuilt js/jquery function that converts 1 to first, 2 to second, 3 to third... etc.?

ex:

Num2Str(1); //returns first;
Num2str(2); //returns second;

I dont want to write a function for 100 numbers. Please help.

umm, show code for starters.., also we do not do your homework — Vogel612, Dec 06 '13 at 14:05
The answer is no. but you can write your own function which will be the one of the most useless functions of all time — FreshPro, Dec 06 '13 at 14:09
@FreshPro i have to be disagree concerning usefulness of this kind of function — A. Wolff, Dec 06 '13 at 14:11
Take a [look at this](http://javascript.about.com/library/bltoword.htm), I think this could be what your looking for. Although it doesn't use first, second etc. but one, two, three etc. — AfromanJ, Dec 06 '13 at 14:11
@Vogel612 I did not start writing the code yet. I am searching for a built in function to avoid writing it. Looks like there is none available. Tibos and Vogel612: Thanks for the pointers. They are very helpful! — EvilDevil, Dec 06 '13 at 15:55
I did not know the term ordinals. Hence, couldn't find the relevant thread :( Sorry for the duplicate post. — EvilDevil, Dec 06 '13 at 15:58

score 42 · Accepted Answer · edited Feb 10 '17 at 09:20

42

There is no inbuilt function for it.

I did write one for up to 99:

var special = ['zeroth','first', 'second', 'third', 'fourth', 'fifth', 'sixth', 'seventh', 'eighth', 'ninth', 'tenth', 'eleventh', 'twelfth', 'thirteenth', 'fourteenth', 'fifteenth', 'sixteenth', 'seventeenth', 'eighteenth', 'nineteenth'];
var deca = ['twent', 'thirt', 'fort', 'fift', 'sixt', 'sevent', 'eight', 'ninet'];

function stringifyNumber(n) {
  if (n < 20) return special[n];
  if (n%10 === 0) return deca[Math.floor(n/10)-2] + 'ieth';
  return deca[Math.floor(n/10)-2] + 'y-' + special[n%10];
}

// TEST LOOP SHOWING RESULTS
for (var i=0; i<100; i++) console.log(stringifyNumber(i));

DEMO: http://jsbin.com/AqetiNOt/1/edit

edited Feb 10 '17 at 09:20

Fuzz

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answered Dec 06 '13 at 14:18

Tibos

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This is great. Thank you. However, the spelling of "fourtieth" is wrong. It should be "fortieth"... not to be a spelling nazi or anything. Just figured I'd point that out. – Elliot Larson Sep 20 '14 at 17:33
2

@Elliot this looks like a british vs american english thing to me... – Vogel612 Sep 21 '14 at 20:51
It was useful... Thanks – Swastik Jan 19 '18 at 09:31

Vogel612 · Answer 2 · 2013-12-06T14:25:07.200

4

You could create a numberbuilder:

You will need to create a foolproof way to convert the single digits by power to a string.

1234 -->1(one)*10^3(thousand)+2(two)*10^2(hundred)+3(three)10(ten)+4(four)(one)
==> one thousand two hundred th irty four th

123456 --> one hundred tw enty three thousand four hundred fi fty six th

if you are wondering about the notation: I tried to split this up in the single decision steps you need to make

the rules for building repeat every three digits. The rest is up to you.

Oh and before I forget: there is only "3" exceptions to the th-rule. one, two and three.

edited Dec 06 '13 at 14:25

answered Dec 06 '13 at 14:16

Vogel612

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I guess, you did homework for him. I don't consider you as starter, do you? – Anand Jha Dec 06 '13 at 14:18
@anand4tech you mean, tibos did the homework and i just showed him how he didn't need to write a switch case for every number possible?? – Vogel612 Dec 06 '13 at 14:20
@anand4tech The answer is useful not necessarily for him, but for others as well. – Tibos Dec 06 '13 at 14:20
@Vogel612: +1 for pointing out the three exceptions! – EvilDevil Dec 06 '13 at 16:01
1

Try using the following library: https://github.com/marlun78/number-to-words – omarjebari May 09 '18 at 10:41

How to replace 1 with first, 2 with second,3 with third etc

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