Concatenating longs and floats into a long

Question

I have two numbers:

1234567890 <--- Long

and

0.123456 <--- Float

Is there any way to combine these to make a float(or double) in the following format:

(123)4567890.123456

I don't mind if the numbers in brackets have to be removed.

This worked, thanks. Do you want to put it as an answer so I can mark it as the correct one. I've been given a time (the seconds as an int and the decimal part as a double) and I need to concatenate them so I can work out an interval. — Alex, Dec 06 '13 at 01:29

Eric Postpischil · Accepted Answer · 2013-12-06T01:34:26.923

Given a long l and a float f, you can use:

double result = l % 10000000 + (double) f;

This will usually lose some accuracy in the fraction portion.

Update: From a comment, we learn that these values are a time represented as a number of seconds and a fraction of a second and that it is desired to calculate an interval. If we want to find the difference between two times, then we can calculate the difference with fewer problems from accuracy and precision this way:

double SubtractTimes(long l0, float f0, long l1, float f1)
{
    long ld = l1 - l0;
    double fd = (double) f1 - f0;
    return ld + fd;
}

Note: If there is a concern that the time may have wrapped around some upper limit, then the code should test for this and make adjustments.

score 0 · Answer 2 · answered Dec 06 '13 at 01:22

0

I must be missing something. Isn't it as easy as this?

long l = 1234567890;
float f = 0.123456;

float result = l + f;

answered Dec 06 '13 at 01:22

John Wu

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In the most-used current C implementations, this produces 1234567936. – Eric Postpischil Dec 06 '13 at 01:23
Yes, this is the case. – Alex Dec 06 '13 at 01:25

score 0 · Answer 3 · answered Dec 06 '13 at 01:29

0

Use this:

double result = l + f;
printf("%.6f",result);

answered Dec 06 '13 at 01:29

Kaustav Ray

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Concatenating longs and floats into a long

3 Answers3