Lazy Instantiation not working iOS

Question

I've declared a property in the .h file called cellTitles. In my .m file, I have a method as follows:

-(NSArray *)cellTitles
{
    if(!_cellTitles){
        _cellTitles = [[NSArray alloc] initWithObjects:@"several strings", nil];
        NSLog(@"Home Array Created");
    }
    return _cellTitles;
}

But the array is not created when I refer to _cellTitles or self.cellTitles. I have several NSLogs that all say the array has 0 objects. Do I need more than this. Some answers have said I need to synthesize, but as I understand it, that is no longer necessary.

Can you show your property declaration, and show the code you're using to access the property? — godel9, Dec 05 '13 at 05:34
As a guess, is _cellTitles already being created in the class constructor? — Josh B, Dec 05 '13 at 05:35
Have you set a breakpoint verifying that this code is called? Is your property declared as (nonatomic,strong)? – — Aaron Bratcher, Dec 05 '13 at 13:38

karlofk · Answer 1 · 2013-12-05T15:24:41.420

0

Make sure your property is assigned strongly.

@property (nonatomic, strong) NSArray *cellTitles;

edited Dec 05 '13 at 15:24

answered Dec 05 '13 at 15:16

karlofk

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this is not right, you can have a weak property lazy loaded if you want – wattson12 Dec 05 '13 at 15:21
True, but in this case it doesnt seem like the any other object holds a strong reference to the array. Edited the answer. – karlofk Dec 05 '13 at 15:24
1

Most of the time you want objects which have mutable subclasses to be `copy` .. just saying ;) – HAS Dec 05 '13 at 15:39

Lazy Instantiation not working iOS

1 Answers1