Javascript regex .test fails to reject after applying .compile()

Asked Dec 05 '13 at 05:18

Active Dec 05 '13 at 05:38

Viewed 58 times

I am relatively new to javascript.
Following code explains my issue:

var termList = ["style", "model"];
var nodeValidRegexStr = "(?:" + termList.join("|") + ")+"

var nodeValidRegex = RegExp(nodeValidRegexStr);    
nodeValidRegex.test("mode")
false

nodeValidRegex.compile()
nodeValidRegex.test("mode")
true

Can someone figure out whats goes wrong after compile() ? Thanks in advance!

edited Dec 05 '13 at 05:38

asked Dec 05 '13 at 05:18

Nullpoet

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FWIW, `.compile` is deprecated: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Deprecated_and_obsolete_features#RegExp_Methods. – Felix Kling Dec 05 '13 at 05:22
http://stackoverflow.com/questions/884762/javascript-whats-the-point-of-regexp-compile Note that the pattern after calling `.compile()` looks like `/(?:)/` (at least in Chrome) – Michael Berkowski Dec 05 '13 at 05:22
^^^ which matches everything. – Felix Kling Dec 05 '13 at 05:24
Thanks for the info. So, if .compile() is deprecated does it mean that RegExp() itself always compiles the regex? – Nullpoet Dec 05 '13 at 05:40
Curious what it is you're actually trying to do? What's the end result here? – brandonscript Dec 05 '13 at 07:24

Javascript regex .test fails to reject after applying .compile()

0 Answers0