How to check a variable value is in an array?

Question

How to check php variable with array?

When $user_check = "ccc";

<?php
    $user_group = array('aaa' , 'bbb' , 'ccc' , 'ddd');
    $name_group = join("','",$user_group); 

    if ($name_group != $user_check) { 
        echo "not found." 
    } else { 
        echo "found." 
    }
?>

Mahmood Rehman · Accepted Answer · 2013-12-04T07:44:33.330

4

Try in_array()

if (in_array($user_check,$user_group))
{ echo "found."; }
else
{ echo "Not found."; }

Check the documentation on this link.

edited Dec 04 '13 at 07:44

answered Dec 04 '13 at 07:35

Mahmood Rehman

4,303
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+1 , Link the documentation too. – Shankar Narayana Damodaran Dec 04 '13 at 07:38
please add semicolon after echo statement. other then it will give an error. – harry Dec 04 '13 at 07:44
Not critical, but this could simplified to a one liner: `echo in_array($user_check,$user_group) ? 'found' : 'not found'`. – Boaz Dec 04 '13 at 08:11

score 0 · Answer 2 · edited Dec 04 '13 at 07:41

0

Use in_array Function

if ( in_array($user_check, $user_group) ) {
   echo "found."
} else { 
  echo "not found."
}

edited Dec 04 '13 at 07:41

Mihai Stancu

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answered Dec 04 '13 at 07:36

Pankaj Pareek

3,806
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Your code returns `found.` in both cases. – Boaz Dec 04 '13 at 07:37
thanks .. this just missed in typiing :) – Pankaj Pareek Dec 04 '13 at 07:38

How to check a variable value is in an array?

2 Answers2