Match float numbers separated by semicolon

Question

I use a regexp validator and I want to restrict the use of anything but the pattern:

5414.1;123;412.1;41241;...

I tried to use [0-9;\.]* but I can't make it match only patterns which contain one(1) point after the text and before ;.

I tested using http://regexpal.com/.

xsc · Answer 1 · 2013-11-29T13:57:34.263

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If the data has to end with a ;:

 (-?\d+(\.\d+)?\;)+

Otherwise:

 (-?\d+(\.\d+)?)(;-?\d+(\.\d+)?)*;?

These will not allow empty input but you can achieve that behaviour by replacing the + in the first example with * and by wrapping the second one in (...)?.

edited Nov 29 '13 at 13:57

answered Nov 29 '13 at 13:52

xsc

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score 4 · Answer 2 · answered Nov 29 '13 at 16:23

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^(\d+(\.\d+)?;)+$

the ^$ will prevent accepting a part of the string

answered Nov 29 '13 at 16:23

user3050022

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score 2 · Answer 3 · answered Nov 29 '13 at 16:34

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you could also use this pattern

^(?:-?\d+[.;]?)+$

answered Nov 29 '13 at 16:34

alpha bravo

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peterh · Accepted Answer · 2021-12-07T18:56:51.423

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That is not perfect, too, but is already in the near... for example it allowed -01.5.

((-|)[0-9]+(\.[0-9]*[1-9]|)\;)*(-|)[0-9]+(\.[0-9]*[1-9]|)

Instead an (x|) -like expression you can also use x?. (Thanks @OGHaza)

edited Dec 07 '21 at 18:56

answered Nov 29 '13 at 13:50

peterh

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Might be nitpicking but using `x?` seems much clearer than `(x|)`. – OGHaza Nov 29 '13 at 14:02

Match float numbers separated by semicolon

4 Answers4