Linux - How to list all users and their UIDs

Question

How to write a script for linux which list all users from /etc/passwd and their UID

User1 uid=0001
User2 uid=0002
...

the script should use: grep, cut, id, for

This really isn't a homework platform. – SBI Nov 28 '13 at 14:24 — SBI, Nov 28 '13 at 14:24

score 34 · Accepted Answer · answered Nov 28 '13 at 14:30

awk -F: '$0=$1 " uid="$3' /etc/passwd

awk is easier in this case.

-F defines field separator as :

so you want is 1st and 3rd colums. so build the $0 to provide your output format.

this is very basic usage of powerful awk. you may want to read some tutorials if you faced this kind of problem often.

This time you got fish, if I were you, I am gonna do some research on how to fishing.

score 9 · Answer 2 · answered May 01 '14 at 19:35

9

cut is nice for this:

cut -d: -f1 /etc/passwd

This means "cut, using : as the delimeter, everything except the first field from each line of the /etc/passwd file".

answered May 01 '14 at 19:35

Will

Sanjar Stone · Answer 3 · 2014-11-02T08:09:48.920

4

I think best option is as that:
grep "/bin/bash" /etc/passwd | cut -d':' -f1

edited Nov 02 '14 at 08:09

answered Nov 02 '14 at 07:33

Sanjar Stone

1

this answer is what I am looking for. It gives users that can login using GUI :) – Alex Jones Jan 13 '15 at 13:06

score 1 · Answer 4 · answered Feb 10 '16 at 12:26

1

awk  -F':' '$3>999 {print $1 " uid: " $3}' /etc/passwd | column -t | grep -v nobody

Gives you all regular users (uid >= 1000) neatly ordered including the userid.

answered Feb 10 '16 at 12:26

sjas

4 Answers4