Binding function with more arguments than needed and passing definite arguments to it

Question

Let I have a function

void f1(type_a a, type_b b, type_c c)

I want to convert it to

void f2(type_a a, type_b b)

where instead of c will be passed my object.

How can I do this usind boost:bind?

score 1 · Answer 1 · answered Nov 19 '13 at 07:40

1

Something like this I think

boost::bind(&f1, _1, _2, c_default_value);

answered Nov 19 '13 at 07:40

ForEveR

I tried, but recieved a compiller error "error: invalid use of 'void'" – w00drow Nov 19 '13 at 07:45
@w00drow on which line? `type_c c_default_value; boost::bind(&f1, _1, _2, c_default_value)(a, b);` – ForEveR Nov 19 '13 at 07:58

score 0 · Answer 2 · answered Nov 19 '13 at 11:13

C++ is not a functional language, so you can't make a true partial application of a function. What you can do is the following:

#include <boost/bind.hpp>
void f1(int a, double b, char c)
{}
int main()
{
  auto binder = boost::bind(&f1, _1, _2, 'c');
  binder(1, 2.0);
}

Note however, that while you can pass binder to any context where a callable is expected, it is not convertible to a pointer-to-function.

2 Answers2