Process.Start starts the process two times instead of one

Question

I got two executables (Program1.exe and Program2.exe) which each open the other one when closed:

Here some code from Program1.exe:

private void Main_FormClosing(object sender, FormClosingEventArgs e)
{
   Application.Exit();
   Process.Start(Environment.CurrentDirectory + @"\Program2.exe");
}

However, when I do this, it opens two windows instead of one. Is there any way to let it open one window only?

@Closevoter did you tried first? – Sriram Sakthivel Nov 16 '13 at 09:39 — Sriram Sakthivel, Nov 16 '13 at 09:39

score 2 · Accepted Answer · answered Nov 16 '13 at 09:38

Application.Exit will call FormClosing event one more time. So Process.Start is called twice and thus it opens twice.

Move the following code in FormClosed event

private void Main_FormClosed(object sender, FormClosedEventArgs e)
{
    Process.Start(Environment.CurrentDirectory + @"\Program2.exe");
}

score 2 · Answer 2 · answered Nov 16 '13 at 09:39

2

Try removing Application.Exit();.

It calls Main_FormClosing

answered Nov 16 '13 at 09:39

Jerry

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Process.Start starts the process two times instead of one

2 Answers2