22

I am trying to display a filtered list of of products, based on Category filter and ItemsPerPage but I'm having some issues when trying to use it with PagedList.

Someone with PagedList expertise could advice me if I need to write my own pagination code or is there a way to get the results I need using PagedList.

I am using LINQ's Skip & Take functions to get only the number of rows that need to be displayed on the current page, but I would still like paging links to show pages based on the filter's total count.

E.g.: my search filter finds 50 results, but since my rows per page is say 10 items, I use LINQ's Skip() & Take() to get only 10 rows back. I still need to show in my View.cshtml the page links << 1 | 2 | 3 | 4 | 5 >> Right now with default PagedList, I only get << 1 >>, I know why I only see one page but just wanted to know how can I make it work to show correct number of page links, while only getting a subset of results.

**My goal is to write optimized queries to the Database so the web page response performance will be fast.

Here is what my code for the Action Method looks like. The code is getting the correct results but the pagination is not working as I need it to be:

public ViewResult List(int page =1, string category =null)
{
    if (category != null) this.CurrentCategory = category;

    var products = repository.Products
                    .Where(p => this.CurrentCategory == null || p.Category == this.CurrentCategory)
                    .OrderBy(p => p.ProductID)
                    .Skip((page -1) * PageSize)
                    .Take(PageSize);

    return View(products.ToList().ToPagedList(page, PageSize));
}

Here is the code snippet from the View that deals with pagination. I looked into the project's Github site but could not find an extension method to provide custom pages. I think it will only render number of pages based on 'items per page' and the Count() of products in the @Model:

@model IPagedList<Product>

//foreach loop that renders the @Model

//Code that displays the pagination using PagedList
<div style="text-align:center">
    @Html.PagedListPager(Model, page => Url.Action("List", new { page = page, category =  ViewBag.CurrentCategory }), PagedListRenderOptions.OnlyShowFivePagesAtATime
    )
</div>
Daniel
  • 9,491
  • 12
  • 50
  • 66
badboy11
  • 541
  • 1
  • 6
  • 19
  • Did you ever get this answered? I have the same problem and I don't see myself retrieving all the records so that we can have a proper paging number display. Please let me know – Johnny Dec 24 '13 at 18:04
  • Hi Johnny, the answer is for custom filtering, you would need to write your own code to handle pagination. PagedList is a great pagination library but it does not provide filtering and returning only subset for optimization for a huge list of data. – badboy11 Feb 17 '14 at 23:57
  • Then What is the finial Answer to achieve this ????? – Vinod Dec 22 '14 at 07:28

5 Answers5

27

I had the exactly same problem and I ended up using StaticPagedList. You can do something like this

public ViewResult List(int page =1, string category =null)
{
    if (category != null) this.CurrentCategory = category;

    var products = repository.Products
                   .Where(p => this.CurrentCategory == null || p.Category == this.CurrentCategory)
                   .OrderBy(p => p.ProductID)
                   .Skip((page -1) * PageSize)
                   .Take(PageSize);

var count = repository.Products
                   .Where(p => this.CurrentCategory == null || p.Category == this.CurrentCategory).Count();

var resultAsPagedList = new StaticPagedList<Product>(products, page, PageSize, count);

    return View(resultAsPagedList);
}

as for the view, you just need to replace the model type

@model StaticPagedList<Product>
mpricochi
  • 271
  • 3
  • 3
3

You will still likely have to ask for a count separately.

var products = repository.Products
                         .Where(p => this.CurrentCategory == null || p.Category == this.CurrentCategory);
var numProds = products.Count();
var mypage = products.OrderBy(p => p.ProductID)
                     .Skip((page -1) * PageSize)
                     .Take(PageSize);
Michael Dunlap
  • 4,300
  • 25
  • 36
  • Thank you for your response. My question is how to customize PagedList framework to display a custom paging scheme. I know how to filter my search and get a results.Count(). But so far all my tries to plug the Count() into the PagedList has failed. Before I start writing my own custom pagination I wanted to see if I could achieve the customization using PagedList, since it is a nice pagination framework. – badboy11 Nov 13 '13 at 00:44
  • Ahh. You'll have to share your view code as well to see if there's something wrong there. – Michael Dunlap Nov 13 '13 at 17:39
  • Hi DigitalD, I updated my first posting to show the View's Razor/C# code to display the pagination code. – badboy11 Nov 13 '13 at 18:26
  • @MonojitSarkar Yes it would hit the DB twice. Once for the total count, and once for loading the filtered page of results. – Michael Dunlap Feb 02 '18 at 17:05
3

ToPagedList uses Take and Skip internally and when you use the extension to the IQueryable<T> class, that will result in the database query you require. It also retrieves the TotalItemCount into its Metadata.

Sometimes you may need to bring the query results into memory because you are using a method that cannot be translated into sql. That means you have to convert the PagedList back to an Enumerable. You can get around this problem by using the StaticPagedList method like this:

   var superset= repository.Products
      .Where(p => this.CurrentCategory == null 
             || p.Category == this.CurrentCategory)
      .OrderBy(p => p.ProductID)
      .ToPagedList(page, PageSize);

   var subset = superset
      .AsEnumerable()
      .Select(p => new ProductViewModel
      {
          OtherData = p.UntranslateableMethod()  
      })

    var model = new StaticPagedList<ProductViewModel>(subset,
       superset.GetMetaData());
}

From the summary of the method in comments:

Initializes a new instance of the PagedList.StaticPagedList class that contains the already divided subset and information about the size of the superset and the subset's position within it.

Colin
  • 22,328
  • 17
  • 103
  • 197
  • This is the correct answer. You can get the total list of items by just calling 'OnePageOfItems.TotalItemCount' I ran through the SQL and timing with miniprofiler. You can make two calls (one to count the total objects, and then one to get the list of objects themselves), and pass them into a static paged list. However, making a call to IPagedList with an IOrderedQueryable will result in exactly the same SQL calls internally. So it makes more sense to do that and then call .TotalItemCount. – mcfroob Dec 19 '16 at 01:27
2

If you use PagedList's methods, you do not need to also use LINQ .skip() and .take(). If you do, then you are pre-limiting the list, and it would be pointless to use the library because you are first filtering down the list to get pagesize results by .skip() and .take() then passing those pagesize results to be filtered again down to pagesize, which will of course be the same, but then PagedList doesn't know what the total is.

If you want to ensure you are not loading all results, simply send an IQueryable to PagedList instead of an Enumerable or List. PagedList will add the .Skip() and .Take() for you, and your database will only return those results.

solidau
  • 4,021
  • 3
  • 24
  • 45
  • 1
    Thank you Juventus18 for your feedback, but please read the question carefully and understand it before trying to answer. – badboy11 Feb 17 '14 at 23:52
  • @badboy11 `and understand it` seems a bit harsh. If someone does not already understand something... how likely is it... that they would miraculously come to the realization that they are misunderstanding the question. `please read the question carefully` in my opinion... was all that was needed to be said. Don't discourage people, or at the least be more constructive with your criticism. – Chef_Code Apr 13 '16 at 16:50
  • 1
    @badbou11 - I understand what you wrote perfectly. Maybe you didn't write your question very well. "how can I make it work to show correct number of page links, while only getting a subset of results." As I said, this is because you are pre-limiting your list before passing it to `PagedList`. Do not use `.Skip()` and `.Take()` in your query, as `PagedList` will do that for you. if you pass paged list only 10 items (or, a query that returns only 10 items) as you have done and tell it 10 items per page, that is only one page, so it will only render one page. – solidau Apr 13 '16 at 18:25
  • 1
    If you want to ensure your database only returns the paged results instead of the entire set, send `PagedList` an `IQueryable` from your repo instead of `IEnumerable` or `IList` (it is not clear from your example what is returned by your repos). In either case, you do not need to use `Skip()` or `Take()` before passing the result to `PagedList` – solidau Apr 13 '16 at 18:30
1

The above explanation is correct. But when you are assigning Static select list..

new StaticPagedList<Product>(products, page, PageSize, count);.

It displays less number of page link from actual count. If Count is 10 it show only 2 pages if your page size is 5..

If you want to show all pages link availabe in count, then

pass count*5 ie count*pagesize

new StaticPagedList<Product>(products, page, PageSize, count*5);//in my case page size is 5

or new StaticPagedList(products, page, PageSize, count*pagesize);

thus it provide all available counts in pages.

Abhi
  • 11
  • 3