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I have to find the days until an expiration date. I tried to use diff method of DateTime class.

$dataexp = 2013-11-06 00:00:00 ;
$now = 2013-11-05 13:00:00 ;

$dtn = new DateTime('now');
$dte = new DateTime($dataexp);

$diff = $dtn->diff($dte);

$days = sprintf("%01d", $diff->days);

$days ---> display 1

My problem is if the dataexp is in the past of 1 day the result of diff is 1 and not -1

$dataexp = 2013-11-04 00:00:00 ;
$now = 2013-11-05 13:00:00 ;

$dtn = new DateTime('now');
$dte = new DateTime($dataexp);

$days = sprintf("%01d", $diff->days);

$days ---> display 1

What method could I use to get what I want? (-1 days)? Thanks

John Conde
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Paolo Rossi
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    `diff` needs formatting to show the proper value. #Look at the examples in the manual. http://php.net/manual/en/datetime.diff.php – Pekka Nov 05 '13 at 14:42
  • "`display 1`" - what does that mean exactly? The code you show displays nothing. – deceze Nov 05 '13 at 14:45

1 Answers1

2

See DateInterval::format(), specifically the r format character.

echo $diff->format('%r%d');
John Conde
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