I wanted to know if boost has any libraries that assist in implementing spin locks. I know boost supports mutexes but I could not find any examples that show or describe spinlocks in boost.Any examples showing how to implement a spin lock using boost(preferably) would be appreciated.(C++98)
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Example using Boost.Atomic
:
#include <boost/atomic.hpp>
class SpinLock
{
boost::atomic_flag flag; // it differs from std::atomic_flag a bit -
// does not require ATOMIC_FLAG_INIT
public:
void lock()
{
while( flag.test_and_set(boost::memory_order_acquire) )
;
}
bool try_lock()
{
return !flag.test_and_set(boost::memory_order_acquire);
}
void unlock()
{
flag.clear(boost::memory_order_release);
}
};
#include <boost/range/algorithm.hpp>
#include <boost/atomic.hpp>
#include <boost/thread.hpp>
#include <iostream>
#include <vector>
class SpinLock
{
boost::atomic_flag flag;
public:
void lock()
{
while( flag.test_and_set(boost::memory_order_acquire) )
;
}
bool try_lock()
{
return !flag.test_and_set(boost::memory_order_acquire);
}
void unlock()
{
flag.clear(boost::memory_order_release);
}
};
int main()
{
using namespace std; using namespace boost;
SpinLock lock;
vector<thread> v;
for(auto i = 0; i!=4; ++i)
v.emplace_back([&lock, i]
{
for(auto j = 0; j!=16; ++j)
{
this_thread::yield();
lock_guard<SpinLock> x(lock);
cout << "Hello from " << i << flush << "\tj = " << j << endl;
}
});
for(auto &t: v)
t.join();
}
Output is:
Hello from 0 j = 0
Hello from 1 j = 0
Hello from 3 j = 0
Hello from 2 j = 0
Hello from 3 j = 1
Hello from 1 j = 1
Hello from 3 j = 2
Hello from 2 j = 1
Hello from 1 j = 2
Hello from 2 j = 2
Hello from 1 j = 3
Hello from 2 j = 3
Hello from 1 j = 4
Hello from 3 j = 3
Hello from 2 j = 4
Hello from 1 j = 5
Hello from 2 j = 5
Hello from 1 j = 6
Hello from 2 j = 6
Hello from 1 j = 7
Hello from 2 j = 7
Hello from 1 j = 8
Hello from 2 j = 8
Hello from 3 j = 4
Hello from 2 j = 9
Hello from 3 j = 5
Hello from 1 j = 9
Hello from 2 j = 10
Hello from 1 j = 10
Hello from 2 j = 11
Hello from 3 j = 6
Hello from 1 j = 11
Hello from 2 j = 12
Hello from 3 j = 7
Hello from 1 j = 12
Hello from 2 j = 13
Hello from 3 j = 8
Hello from 2 j = 14
Hello from 3 j = 9
Hello from 1 j = 13
Hello from 2 j = 15
Hello from 1 j = 14
Hello from 3 j = 10
Hello from 1 j = 15
Hello from 3 j = 11
Hello from 3 j = 12
Hello from 3 j = 13
Hello from 3 j = 14
Hello from 3 j = 15
Hello from 0 j = 1
Hello from 0 j = 2
Hello from 0 j = 3
Hello from 0 j = 4
Hello from 0 j = 5
Hello from 0 j = 6
Hello from 0 j = 7
Hello from 0 j = 8
Hello from 0 j = 9
Hello from 0 j = 10
Hello from 0 j = 11
Hello from 0 j = 12
Hello from 0 j = 13
Hello from 0 j = 14
Hello from 0 j = 15

Evgeny Panasyuk
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Since C++11 there is a [`std::atomic_flag`](https://en.cppreference.com/w/cpp/atomic/atomic_flag), which can be used in place of this implementation. – João Neto Aug 24 '18 at 14:49
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1@joaomlneto Yes, but question was about Boost. – Evgeny Panasyuk Aug 25 '18 at 01:39
0
Here is a sample using C++11 atomic:
#include <atomic>
typedef std::atomic<bool> Lock;
void enterCritical(Lock& lock) {
bool unlocked = false;
while (!lock.compare_exchange_weak(unlocked, true));
}
void exitCritical(Lock& lock) {
lock.store(false);
}

erenon
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1. It is better to use `std::atomic_flag` for that purpose, because it is guaranteed to be lock-free. 2. There is `Boost.Atomic` library which also has `boost::atomic_flag`. – Evgeny Panasyuk Nov 02 '13 at 15:15
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However, the atomic_flag interface is different: http://en.cppreference.com/w/cpp/atomic/atomic_flag -> you can't use compare and exchange, only test and set. – erenon Nov 02 '13 at 15:17
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-
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@erenon Yes, `atomic_flag` has different interface, but it is enough to implement spin-lock. Regarding `standard library` (not `STL`!) - yes, of course it is better to use it if available, but question was about `Boost`, so I presume it is not. – Evgeny Panasyuk Nov 02 '13 at 15:22
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This is not safe implementation. cout seems crumbled together sometimes, but the boost::mutex won't. – Bryan Fok Mar 09 '15 at 08:04
0
The spinlock solution provided by erenon sometimes generated crumble cout result. but the boost::mutext solution won't. So either the solution is incorrect, or my understanding of cout is wrong.
#include <iostream>
#include <thread>
#include <atomic>
#include <boost/thread/mutex.hpp>
using namespace std;
class spinlock {
private:
std::atomic<bool> lock_;
public:
spinlock() {
lock_.store(false);
}
void lock() {
bool unlocked = false;
while (!lock_.compare_exchange_weak(unlocked, true));
}
void unlock() {
lock_.store(false);
}
};
class add_one
{
private:
std::string name_;
unsigned int& num_;
spinlock & lock_;
boost::mutex & mutex_;
public:
add_one(std::string name, unsigned int& num, spinlock &lock, boost::mutex &mutex)
:name_(name),
num_(num),
lock_(lock),
mutex_(mutex)
{
}
void add_and_display()
{
while(true)
{
lock_.lock();
//boost::lock_guard<boost::mutex> g( mutex_);
std::cout << name_ << " " << num_ << endl;
if(num_ == 10000000)
{
return;
}
num_++;
lock_.unlock();
}
}
};
int main()
{
cout << "Hello World" << endl;
unsigned int n = 0;
spinlock lock;
boost::mutex mutex;
add_one one("t1", n ,lock, mutex);
add_one two("t2", n ,lock, mutex);
add_one three("t3", n ,lock, mutex);
//add_one four("t4", n ,lock, mutex);
std::thread t1(std::bind(&add_one::add_and_display, one));
std::thread t2(std::bind(&add_one::add_and_display, two));
std::thread t3(std::bind(&add_one::add_and_display, three));
//std::thread t4(std::bind(&add_one::add_and_display, four));
t1.join();
t2.join();
t3.join();
//t4.join();
return 0;
}

Bryan Fok
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0
Slightly off-topic but relevant -- one can get a lock-free-guaranteed spinlock using C++11 (instead of C++03) without the need for
boost
(although that was the question title).
Using C++11 std::atomic_flag
.
It is always lock-free, as noted by Evgeny Panasyuk in the comments of erenon's answer. std::atomic
seems to not guarantee to be wait-free (which is required in some cases).
Also conforms to the BasicLockable
interface, which can be used by std::lock_guard
/std::scoped_lock
/...
class Spinlock {
std::atomic_flag _lock = ATOMIC_FLAG_INIT;
public:
void lock() {
while (_lock.test_and_set(std::memory_order_acquire)) continue;
}
void unlock() {
_lock.clear(std::memory_order_release);
}
};

João Neto
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