Make Counter.most_common return dictionary

Question

I used the sample from the documentation:

>>> Counter('abracadabra').most_common(3)
[('a', 5), ('r', 2), ('b', 2)]

How can I make the result to be:

{ 'a': 5, 'r' :2 , 'b' :2}

supposing that we want to keep the Counter().most_common() code?

Answer 1

dict will do this easily:

>>> dict(Counter('abracadabra').most_common(3))
{'a': 5, 'r': 2, 'b': 2}
>>>

For further reference, here is part of what is returned by help(dict):

     dict(iterable) -> new dictionary initialized as if via:
 |      d = {}
 |      for k, v in iterable:
 |          d[k] = v

Answer 2

The easiest way is to simply use dict()

dict(Counter('abracadabra').most_common(3))

Output:

{'a': 5, 'r': 2, 'b': 2}