Using continue to skip iteration in foreach from inside a swich

Question

$arr = array('not want to print','foo','bar');

foreach($arr as $item) {
  switch($item) {
      case 'foo':
         $item = 'bar';
         break;
      case 'not want to print':
         continue;
         break;
  }

  echo $item;
}

http://codepad.org/WvW1Fmmo

But "not want to print" is echoed. Why does continue don't apply to the foreach?

You misspelled `switch`. Is that in the real code or a copying error? — Barmar, Oct 26 '13 at 12:11
Hi, thanks; no, it's actually a sample http://codepad.org/Ytkd8x2M — Toni Michel Caubet, Oct 26 '13 at 12:12

Barmar · Accepted Answer · 2013-10-26T12:20:22.553

7

From the http://php.net/manual/en/control-structures.continue.php:

Note: Note that in PHP the switch statement is considered a looping structure for the purposes of continue.

So use continue 2; to continue the loop that contains it.

You also have a mismatch between $arr and case. The first word in the array value is no, but you're checking for not in the case.

Corrected codepad

edited Oct 26 '13 at 12:20

answered Oct 26 '13 at 12:15

Barmar

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Thanks for the heads up, didn't ever heard of it. Actually my code was larger and there where no typos, I tried to reproduce a simpler version of the code, haha. Thanks again! – Toni Michel Caubet Oct 26 '13 at 12:33

Using continue to skip iteration in foreach from inside a swich

1 Answers1