storing the output of boost::bind in a boost::function

Question

I currently have something like this

void asomeMethod(int q)
{
    std::cout << "Method with parameter " << q ;
}

int main()
{
     boost::function<void(int)> parfunct;
     parfunct = boost::bind(&asomeMethod,12);
     parfunct;  //Does not call asomeMethod ??
    return 0;
}

I want to call the function ptr but the method is not being called ? Any suggestions on what I might be doing wrong ?

score 1 · Accepted Answer · answered Oct 25 '13 at 18:52

1

It has to be boost::function<void()>, since there's no remaining argument.

Then call it like a function:

parfunct();

answered Oct 25 '13 at 18:52

Kerrek SB

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in that case I get Error `error C2064: term does not evaluate to a function taking 0 arguments` – Rajeshwar Oct 25 '13 at 18:53
@Rajeshwar: Sorry, fixed. Extraneous arguments in `bind` are ignored, subtle error... The `function` type needs to be what you *call*, not the input of `bind`. – Kerrek SB Oct 25 '13 at 18:54

storing the output of boost::bind in a boost::function

1 Answers1