How to access elements in external views in titanium alloy?

Question

I am making android mobile app on titanium Alloy 1.2.2

I want to access elements contained in external views. So if I use

var win=Alloy.createController().getView();

it itself opens that view. I dont need that. I just want to access an element in that view and change its visibility to false. How can we do that? Thanx in advance.

You can access the child elements of your view, for example if you have your main view and you want to access a label inside another controller which has another view you'll have to do something similar to this: `mainView.children[0].children[0].children[0]` — Mario Galván, Oct 22 '13 at 19:28

score 1 · Answer 1 · answered May 09 '15 at 06:20

1

use Alloy.createController('name').__views to get views outside the controller, e.g.:

// fruit.xml
<Alloy>
    <View id='opacity_view'></View>
</Alloy>

// other.js: 
the_view = Alloy.createController('fruit').__views.opacity_view

answered May 09 '15 at 06:20

Siwei

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score 0 · Answer 2 · answered Oct 22 '13 at 19:37

Another solution is to export the property but you'll need the reference of your controller which you already have it.

var win=Alloy.createController('Path to your controller');

In the .js of the controller you need:

exports.element = $.elementid;

Then you can access win.element.visible = false or whatever property you need.

score 0 · Answer 3 · answered Oct 23 '13 at 01:28

controller.getView() doesn't show view on the screen. Probably in controller which you initialize you have code similar to this: $.index.open() which adds new view on device screen.

If you want to hide element when view is created the best way is to create .tss file where you put rule: visible: false using either #id or .class.

Check more in Alloy Styles and Themes documentation.

How to access elements in external views in titanium alloy?

3 Answers3