How do I format a long integer as a string without separator in Java?

Question

Simple question, but I'll bet that asking on here will probably be more straight forward than trying to understand the documentation for MessageFormat:

long foo = 12345;
String s = MessageFormat.format("{0}", foo);

Observed value is "12,345".

Desired value is "12345".

score 397 · Answer 1 · answered Dec 21 '09 at 19:38

397

MessageFormat.format("{0,number,#}", foo);

answered Dec 21 '09 at 19:38

Daniel Fortunov

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Thanks, I was trying to do this with MessageFormat properties injection. Good thing there's more than one way to do it! – Philihp Busby Oct 20 '11 at 02:27
5

i prefer this way. since it allows me to change the format in my language properties file. – Pascal Mar 05 '12 at 10:17
Nice..!! @daniel-fortunov Can you please explain what and how its done ? – Aman Gupta Dec 30 '14 at 06:22
3

Perfect solution! Helped me keep the format/unformat option in reference data instead of at code level - thanks! And as @SebastianRoth said - this should have been the accepted answer. – Ofer Lando Apr 13 '15 at 08:54
This doesn't not work for Java8. Locale still intrudes and if your locale has setGroupingUsed==true then you will get grouping symbols injected. Very problematic if you only want certain integers to not have default locale grouping symbols. – William May 17 '16 at 10:15
12

I'm actually surprised why prettying numeric strings a default and not an explicit thing with the formatter API – humblerookie Jun 25 '17 at 14:40
1

This worked perfectly, thank you. I'm using the buildnumber Maven plugin and it kept formatting the build number with a comma, no matter what I put inside the element. – Aquarelle Nov 15 '17 at 09:02
4

This works also inside a choice format if you quote the pattern: `MessageFormat.format("{0,choice,0#no foos|1#one foo|1<'{0,number,#}' foos}"` – GOTO 0 Dec 01 '17 at 10:39
@GOTO0 I only just noticed that way back in 2017 you posted this comment. No up-votes so it was hidden to me (hopefully fixed now!). My posted answer basically says the same thing, with a much more elaborate example. – Christopher Schultz May 07 '20 at 16:58
This works. I searched a lot and got this solution. – Bruce wayne - The Geek Killer Feb 17 '22 at 19:47

score 81 · Accepted Answer · edited Jan 22 '16 at 20:19

81

Just use Long.toString(long foo)

edited Jan 22 '16 at 20:19

randers

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answered Dec 21 '09 at 19:35

Rob H

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String.valueOf() calls Long.toString() – Peter Lawrey Jan 04 '10 at 11:00
8

Maybe this is trifling but in this case you're relying on an undocumented behavior of Long.toString(foo). For that reason, I prefer Daniel Fortunov's answer. – John K Aug 27 '10 at 22:49
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It's not undocumented. See http://download.oracle.com/javase/6/docs/api/java/lang/Long.html#toString%28long%29. – Rob H Aug 28 '10 at 00:53
Rob H: Oh, you're right, though I'd point at the docs for Long#toString(long, int) – John K Aug 31 '10 at 15:15
6

OK, however this solution is not applicable to message formatting in ResourceBundle. [Tuto i18n](https://docs.oracle.com/javase/tutorial/i18n/format/messageFormat.html) – Guillaume Husta Oct 14 '15 at 09:14
5

If you are using resource bundles, then Daniel Fortunov's answer is definitely preferable. – Jean-François Beauchef May 08 '16 at 23:49
IMO this is a better answer than the accepted one based upon the question. Had the question specified "how do I tell a resource bundle to display a number without separators" then the accepted one would be better. – Christopher Schultz Oct 19 '22 at 21:10

score 4 · Answer 3 · answered May 07 '20 at 14:44

I struggled with this a little bit when trying to do "real world" patterns with internationalization, etc. Specifically, we have a need to use a "choice" format where the output depends upon the values being displayed, and that's what java.text.ChoiceFormat is for.

Here is an example for how to get this done:

    MessageFormat fmt = new MessageFormat("{0,choice,0#zero!|1#one!|1<{0,number,'#'}|10000<big: {0}}");

    int[] nums = new int[] {
            0,
            1,
            100,
            1000,
            10000,
            100000,
            1000000,
            10000000
    };

    Object[] a = new Object[1];
    for(int num : nums) {
        a[0] = num;
        System.out.println(fmt.format(a));
    }

This generates the following output; I hope it's helpful for others who are trying to accomplish the same types of things:

zero!
one!
100
1000
10000
big: 100,000
big: 1,000,000
big: 10,000,000

As you can see, the "choice" format allows us to choose the type of format to use depending upon the value being passed-in to be formatted. Small numbers can be replaced with text (no display of the original value). Medium-sized numbers are shown with no grouping separators (no commas). The largest numbers do include the commas, again. Obviously, this is an entirely contrived example to demonstrate the flexibility of java.text.MessageFormat.

A note about the quoted # in the format text: since both ChoiceFormat and MessageFormat are being used, there is a collision between metacharacters between the two. ChoiceFormat uses # as a metacharacter that essentially means "equals" so that the formatting engine knows that e.g. in the case of 1#one! we are comparing {0} with 1, and if they are equal, it uses that particular "choice".

But # has another meaning to MessageFormat, and that's as a metacharacter which has meaning for DecimalFormat: it's a metacharacter which means "put a number here".

Because it's wrapped up in a ChoiceFormat string, the # needs to be quoted. When ChoiceFormat is done parsing the string, those quotes are removed when passing the subformats to MessageFormat (and then on to DecimalFormat).

So when you are using {0,choice,...}, you have to quote those # characters, and possibly others.

Wow kudos for digging this one, and it's been there since Java 1.1 ! — bric3, May 11 '22 at 09:24

score -1 · Answer 4 · answered Jan 04 '10 at 10:59

-1

The shortest way is

long foo = 12345;
String s = ""+foo;

answered Jan 04 '10 at 10:59

Peter Lawrey

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And, as always, this expands to `new StringBuilder("").append(foo).toString()` so it's not really optimal. – randers Jan 22 '16 at 19:55
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@RAnders00 Converting a number into a single string is unlikely to be the most optimal option, depending on the context you can usually avoid it entirely, but for the simplest pattern you can use `""+` – Peter Lawrey Jan 23 '16 at 19:32
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You are right, but I just wanted to point it out since people always tend to point it out. – randers Jan 23 '16 at 19:33
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@RAnders00 btw using a message format is an order of magnitude more expensive, and more complicated in this case. – Peter Lawrey Jan 23 '16 at 19:36
Yeah, one should instead use `Long.toString()` since it's what this solution uses in the background anyways :) – randers Jan 23 '16 at 19:38
@RAnders00 ... unless you value your developer time more than your CPU time (which is usually the case) – Peter Lawrey Jan 23 '16 at 23:50

score -2 · Answer 5 · answered Dec 21 '09 at 19:39

-2

As an alternative String.format and java.util.Formatter might work for you as well...

answered Dec 21 '09 at 19:39

Frank Grimm

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Need a solution for property file, not code wise. – Bruce wayne - The Geek Killer Feb 17 '22 at 19:49

score -6 · Answer 6 · answered Dec 22 '09 at 04:51

-6

You could try:

String s = new Long(foo).toString();

answered Dec 22 '09 at 04:51

mportiz08

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Unnecessary object creation. Never use new with wrapper classes. – keiki May 11 '15 at 12:24

How do I format a long integer as a string without separator in Java?

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