PHP Operations + Arrays

Question

i need some help.

I have an array ($array) - Array ( [0] => 1374410400 [1] => 1374394500 [2] => 1374384000 [3] => 1374304800 [4] => 1374291900 ).

And the operation that will be used in array is defined by the user. The operation could be array_sum, count and end.

I want to "merge" this two (array + operation), like this $operation.'('.$array.')'.

When I echo this $operation.'('.$array.')'. only appears count(Array).

But when i write "count($res)" appears the result.

Anyone knows the answer?

I have *no* idea what you're trying to do. Can you show us examples and include expected output in your question? — Amal Murali, Oct 14 '13 at 23:19
`echo $operation($array);`, or `echo call_user_func($operation,$array);` — Wrikken, Oct 14 '13 at 23:19

score 0 · Answer 1 · answered Oct 14 '13 at 23:19

0

Looks like you need "variable variables" See documentation

answered Oct 14 '13 at 23:19

Joao

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score 0 · Answer 2 · answered Oct 14 '13 at 23:21

echo $operation.'('.$array.')';

will echo a string formed from string $operation + string ( + string $array + string ).

If you want to execute the operation whose name is stored in $operation, the simplest syntax is:

echo $operation($array);

Note: you almost certainly want to do some validation of the user's input, else you'll get a fatal error if they use an undefined function and so on.

score 0 · Answer 3 · answered Oct 14 '13 at 23:31

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Yes it will only print the string, use the function to get the desired result. function FunctionName($operation, $array){ if($operation =='count'){ return count($array); } }

answered Oct 14 '13 at 23:31

Abbasi

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score 0 · Answer 4 · answered Oct 15 '13 at 08:28

See the documentation for call_user_func().

$results = call_user_func($operation, $array);

Make sure you don't allow the value of the $operation variable to be set directly by the user. Otherwise a malicious user could execute unwanted code on your server. Use the user input to determine which of the operations to run.

PHP Operations + Arrays

4 Answers4