Has boost::function's default constructor the no-throw guarantee?

Question

The question is in the title. I cannot find the information in the reference documentation. I do not see why the default constructor would throw, but I need to be sure it is no-throw to correctly document my exception guarantees.

score 2 · Accepted Answer · answered Oct 10 '13 at 11:10

2

See http://www.boost.org/doc/libs/1_54_0/doc/html/boost/function.html#idp15443616-bb: it explicitly states "Will not throw".

answered Oct 10 '13 at 11:10

richvdh

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Thank you! It was quite easy in fact. I failed to see this was accessible from "Header " in the reference documentation. – Christophe Fuzier Oct 10 '13 at 11:30

Has boost::function's default constructor the no-throw guarantee?

1 Answers1