if an integer is equal to one of the integers in an array?

Question

int[] usedArray = new int[25];

Random generator = new Random ();

int randomNumber = generator.nextInt(2);

System.out.println(randomNumber);

if(randomNumber != usedArray){
app();
}

while(randomNumber == 0){
score();
question1();
System.out.println(randomNumber);
usedArray[1] = 1;
app();
}

error:'incompatible operand types int & int[]'

How can I say if this number is equal to a number within the array without getting an error?

Which number in the array? – Sotirios Delimanolis Oct 09 '13 at 21:13 — Sotirios Delimanolis, Oct 09 '13 at 21:13

score 1 · Answer 1 · answered Oct 09 '13 at 21:14

1

You are comparing an int with an int[], which is plain wrong. If you want to check if the array contains some integer, then you can do:

if (!Arrays.asList(usedArray).contains(randomNumber)) {
    app();
}

answered Oct 09 '13 at 21:14

Rohit Jain

209,639
45
409
525

score 1 · Answer 2 · answered Oct 09 '13 at 21:15

1

You cannot compare a number with an array.

if(randomNumber != usedArray) should be if(randomNumber != usedArray[i]) with i as the index.

answered Oct 09 '13 at 21:15

hazer_drum

253
3
11

if an integer is equal to one of the integers in an array?

2 Answers2