Opening a single CHILD in MDI form

Question

I found the following code from stackoverflow

It works correctly when I execute the MDIParent form as the first form in the project

For Each f As Form In Application.OpenForms
  If TypeOf f Is Form1 Then
    f.Activate()
    Return
  End If
Next

Dim myChild As New Form1
myChild.MdiParent = Me
myChild.Show()

I need to open the LOGIN form as the first form and open MDIParent.

If I open the login form as the first form the above code it not working.. Need a solution

I added this code to a button control

score 0 · Accepted Answer · answered Sep 30 '13 at 09:45

0

Set your Login form as the start form for your project.

On your button, Show the MDI Form (and close the Login form if you wish)

MDI_Main.Show()
Me.Dispose()

Then to open your MDI Child forms, use the following code:

frmChild.MdiParent = Me
frmChild.Show()

This is all the code you should need.

answered Sep 30 '13 at 09:45

Daniel Gee

426
7
21

When I use me.dispose() the project stops – Random User Sep 30 '13 at 09:49
Earlier I used this code, `Dim a As New MDIParent1 a.Show()` I changed it to `MDIParent1.Show()`. Now the code is working – Random User Sep 30 '13 at 09:52
1

If your Login form is your Startup form and you close it, your application will close. You could hide the form with Me.Hide() – Daniel Gee Sep 30 '13 at 09:59

Opening a single CHILD in MDI form

1 Answers1