I am trying to print each char in a variable.
I can print the ANSI char number by changing to this printf("Value: %d\n", d[i]); but am failing to actually print the string character itself.
What I am doing wrong here?
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
int len = strlen(argv[1]);
char *d = malloc (strlen(argv[1])+1);
strcpy(d,argv[1]);
int i;
for(i=0;i<len;i++){
printf("Value: %s\n", (char)d[i]);
}
return 0;
}
You should use %c format to print characters in C. You are using %s, which requires to use pointer to the string, but in your case you are providing integer instead of pointer.
The below will work. You pass in the pointer to a string when using the token %s in printf.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(int argc, char *argv[])
{
int len = strlen(argv[1]);
char *d = malloc (strlen(argv[1])+1);
strcpy(d,argv[1]);
printf("Value: %s\n", d);
return 0;
}
