multiple requests in a single connection?

Question

Is it possible to put multiple requests without breaking the connection using python httplib?. Like, can I upload a big file to the server in parts but in a single socket connection.

I looked for answers. But nothing seemed so clear and definite.

Any examples/related links will be helpfull. Thanks.

score 13 · Accepted Answer · answered Dec 15 '09 at 09:23

13

Yes, the connection stays open until you close it using the close() method.

The following example, taken from the httplib documentation, shows how to perform multiple requests using a single connection:

>>> import httplib
>>> conn = httplib.HTTPConnection("www.python.org")
>>> conn.request("GET", "/index.html")
>>> r1 = conn.getresponse()
>>> print r1.status, r1.reason
200 OK
>>> data1 = r1.read()
>>> conn.request("GET", "/parrot.spam")
>>> r2 = conn.getresponse()
>>> print r2.status, r2.reason
404 Not Found
>>> data2 = r2.read()
>>> conn.close()

answered Dec 15 '09 at 09:23

Pär Wieslander

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would you mind looking at http://stackoverflow.com/questions/18221809/sending-a-few-requests-using-one-connection – Alan Coromano Aug 14 '13 at 03:58
For python 3, replace httplib with http.client – ns15 Jan 25 '23 at 10:08

score 2 · Answer 2 · answered Apr 05 '12 at 18:38

You need to be sure to call the .read() function on your response. Otherwise you'll get an error like:

Traceback (most recent call last):
  File "<pyshell#13>", line 1, in <module>
    conn.request("GET", "/2.html")
  File "C:\Python27\lib\httplib.py", line 955, in request
    self._send_request(method, url, body, headers)
  File "C:\Python27\lib\httplib.py", line 983, in _send_request
    self.putrequest(method, url, **skips)
  File "C:\Python27\lib\httplib.py", line 853, in putrequest
    raise CannotSendRequest()
CannotSendRequest

This exception is raised if the return data has not been read (even if no data is returned, or an HTTP error was recieved [a 404 for example]).

multiple requests in a single connection?

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