java hexadecimal to int conversion - have to remove 0X ?

Question

I have a file with many hex numbers (for eg - 0X3B4 ). Im trying to parse this file as assign these numbers to integers, but dont seem to get Integer.parseInt to work.

   int testint = Integer.parseInt("3B4",16);  <- WORKS

   int testint = Integer.parseInt("0X3B4",16);

gives error:

Exception in thread "main" java.lang.NumberFormatException: For input string: "0x3b4"
        at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)

What is the right way to assign the value 0XB4 to an int ?

Do I have to get rid of the 0X - its not unusual to represent hex nos this way...

score 8 · Accepted Answer · answered Sep 27 '13 at 00:17

8

You can do

int hex = Integer.decode("0x3b4");

You are right that parseInt and parseLong will not accept 0x or 0X

answered Sep 27 '13 at 00:17

Peter Lawrey

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Thanks. Also this doesn't work in java 1.4.1 , I can use it in a higher version though. – Nikhil Sep 27 '13 at 00:33
@Nik I suspect 1.4.1 is ten years old now. ;) – Peter Lawrey Sep 27 '13 at 01:55

java hexadecimal to int conversion - have to remove 0X ?

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