In python, how do I make a raw_input of a list from one number?

Question

I need some code that allows a user to input a number (ie. 5) that creates a list of all the numbers leading up to that number excluding zero (ie. [1,2,3,4,5])

what's the issue you are facing? – Rohit Jain Sep 26 '13 at 17:35 — Rohit Jain, Sep 26 '13 at 17:35

score 1 · Accepted Answer · answered Sep 26 '13 at 17:37

1

>>> range(1,int(raw_input('Number: '))+1)
Number: 5
[1, 2, 3, 4, 5]

answered Sep 26 '13 at 17:37

dawg

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How do I get that to include the original number? In this case 5. – G Warner Sep 26 '13 at 17:41
Refresh your browser. I edited the original answer – dawg Sep 26 '13 at 17:43

score 0 · Answer 2 · answered Sep 26 '13 at 17:38

0

In [11]: L = range(1, int(raw_input("Enter a number: "))+1)
Enter a number: 5

In [12]: L
Out[12]: [1, 2, 3, 4, 5]

answered Sep 26 '13 at 17:38

inspectorG4dget

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score 0 · Answer 3 · answered Sep 26 '13 at 17:39

0

while True:
     try:
        v = int(raw_input('Number: '))
     except:
        print 'Invalid number!!'
     else:
        print range(1,v)
        break

This will prevent the user from inputing an invalid number.

answered Sep 26 '13 at 17:39

Nacib Neme

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In python, how do I make a raw_input of a list from one number?

3 Answers3