Java Base Conversion with addition

Question

How would I do 10101base2 + 111base2 =? I already know how to convert the base to another base. But how would I do them with addition?

Answer 1

I find java's BigInteger to be the best among them all for bit manipulation. Among its wide usages (mainly with storing huge numbers and for its wide array of supported operations), you do have the option for base conversion from 2 to 36. As for addition of these binary digits, you can use BigInteger.add(BigIntger)function provide by them.

Example :

BigInteger num_1=new BigInteger("10101",2);     //Store as Binary
BigInteger num_2=new BigInteger("111",2);       //Store as Binary
BigInteger result=num_1.add(num_2);

//Display the result using BigInteger.toString(int base)
System.out.println("Result = "+result.toString(10));    //Showing result in Decimal base here

Ofcourse, if its having fractional digits, the method described by William Gaul is to be used.

Answer 2

int result = 0b10101 + 0b111;

Or if your inputs are strings:

int result = Integer.parseInt("10101", 2) + Integer.parseInt("111", 2);

EDIT: If you're asking how to view the result in binary form, there's also this:

System.out.println(Integer.toBinaryString(result));