C program, scanf for a char, then reprinting it?

Question

#include <stdio.h>
int main(void)
{
    char fever, cough;

    printf("Are you running a fever? (y/n)\n");
    scanf("%c",&fever);

    printf("Do you have a runny nose/cough? (y/n)\n");
    scanf(" %c",&cough);

    printf("Please verify the folling information.\nFever: %c \nRunny nose/cough: %c \n,fever,cough");
return 0;
}

When I run this I get: 12:2 warning:format '%c' expects a matching 'int' argument [-Wformat]

What do I need to change? I know everything is systematically correct, I just need to use something else, and I can't find anything that specifically fixes my problem!

Thanks guys.

score 1 · Answer 1 · answered Sep 25 '13 at 18:48

printf("Please verify the folling information.\nFever: %c \nRunny nose/cough: %c \n,fever,cough");

Above statement is systematically incorrect. Misplaced " .

MODIFY Like this

printf("Please verify the folling information.\n Fever: %c \nRunny nose/cough: %c \n ",fever,cough);

score 0 · Answer 2 · answered Sep 25 '13 at 18:47

0

Badly placed close quote. Change \n,fever,cough" to \n",fever,cough

answered Sep 25 '13 at 18:47

DrC

7,528
1
22
37

score 0 · Answer 3 · answered Sep 25 '13 at 18:47

You are not placing the ending " quote correctly

printf("Please verify the folling information.\nFever: %c \nRunny nose/cough: %c   \n",fever,cough);
                                                                                     ^ Close your quote here

score 0 · Answer 4 · answered Sep 25 '13 at 18:47

0

You aren't passing the fever or cough parameters to printf. Just add fever and cough as parameters to printf function. Quote should be after text but before variables.

answered Sep 25 '13 at 18:47

Angus Comber

9,316
14
59
107

C program, scanf for a char, then reprinting it?

4 Answers4