twig raw filter and functions

Question

Hi everyone and sorry for my english,

I have a service who generates some html code which is passed to a twig template. I had to use the raw filter to show the code, but in that code I call a twig function.

This is the code stored in a var which is passed to the template by the controller.

'<li class="active" ><a href="{{ path(\'help\') }}">Help</a></li>'

The resulting html code is the same, so {{ path('help') }} is not called.

Is there any filter to show the html code and call the functions?

Thanks

Your service should probably be a twig extension which you then call from inside of your template. — Cerad, Sep 24 '13 at 11:40

score 0 · Answer 1 · edited May 23 '17 at 12:09

0

I answered this before here: Twig: prevent parsing of client-side templates

{% raw %} deprecated

{% verbatim %}
    <ul>
    {% for item in seq %}
        <li>{{ item }}</li>
    {% endfor %}
    </ul>
{% endverbatim %}

edited May 23 '17 at 12:09

Community

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answered Sep 24 '13 at 11:35

Farid Movsumov

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score 0 · Answer 2 · edited May 23 '17 at 12:09

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You should render your variable using the {% include(template_from_string(your_var)) %} twig block.

See the answer of Render content from string/database and generate links with twig for more info.

edited May 23 '17 at 12:09

Community

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answered Sep 24 '13 at 20:21

bjuice

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score 0 · Accepted Answer · answered Sep 25 '13 at 09:04

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In your code, you are using {{path('help')}} for the hyperlink. Instead of using the twig path function, include the original Url in the code that is sent from the service. In the service. use

'<li class="active" ><a href="'.$this->container->get('router')->generate('help').'">Help</a></li>'

answered Sep 25 '13 at 09:04

Praveesh

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That's exactly what I've done, I included the container as argument of my service and it generates all the href using the router component. Thanks for your help – Javi Sep 25 '13 at 13:25

twig raw filter and functions

3 Answers3