'NoneType' object is not subscriptable?

Question

list1 = ["name1", "info1", 10]
list2 = ["name2", "info2", 30]
list3 = ["name3", "info3", 50]
MASTERLIST = [list1, list2, list3]


def printer(lst):
    print ("Available Lists:")
    for x in range(len(lst)):
        print (lst[x])[0]

This code is returning the "'NoneType' object is not subscriptable" error when I try and run

printer(MASTERLIST)

What did I do wrong?

The mistake that you are making is that you are whitespacing print function call wrong, it should be `print(list[x])[0]` according to PEP8, and your mistake becomes more obvious. ;) — Antti Haapala -- Слава Україні, Sep 18 '13 at 08:03
Though the error message is different, this is basically the same problem as [NoneType has no attribute 'something'](/questions/8949252/why-do-i-get-attributeerror-nonetype-object-has-no-attribute-something) — tripleee, Nov 06 '20 at 13:52

score 21 · Answer 1 · answered Sep 18 '13 at 08:00

21

The print() function returns None. You are trying to index None. You can not, because 'NoneType' object is not subscriptable.

Put the [0] inside the brackets. Now you're printing everything, and not just the first term.

answered Sep 18 '13 at 08:00

TerryA

58,805
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score 14 · Answer 2 · answered Sep 18 '13 at 07:54

14

The [0] needs to be inside the ).

answered Sep 18 '13 at 07:54

Ethan Furman

63,992
20
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score 2 · Answer 3 · answered Sep 18 '13 at 08:24

Don't use list as a variable name for it shadows the builtin.

And there is no need to determine the length of the list. Just iterate over it.

def printer(data):
    for element in data:
        print(element[0])

Just an addendum: Looking at the contents of the inner lists I think they might be the wrong data structure. It looks like you want to use a dictionary instead.

score 2 · Answer 4 · answered Oct 24 '16 at 22:25

2

Point A: Don't use list as a variable name Point B: You don't need the [0] just

print(list[x])

answered Oct 24 '16 at 22:25

Cam92

21
4

score 1 · Answer 5 · answered Mar 25 '17 at 12:48

1

The indexing e.g. [0] should occour inside of the print...

answered Mar 25 '17 at 12:48

keremistan

414
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score 1 · Answer 6 · answered Mar 25 '17 at 12:54

1

list1 = ["name1", "info1", 10]
list2 = ["name2", "info2", 30]
list3 = ["name3", "info3", 50]

def printer(*lists):
    for _list in lists:
        for ele in _list:
            print(ele, end = ", ")
        print()

printer(list1, list2, list3)

answered Mar 25 '17 at 12:54

Joshua Nixon

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25

'NoneType' object is not subscriptable?

6 Answers6

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