JDBC transaction, execution order of sql statements

Question

I have following JDBC code:

Connection conn = connectUserDataSource();
        // Setting auto commit to false to execute all queries as part of transaction
        conn.setAutoCommit(false);
        PreparedStatement deletePreparedStatement = null;
        PreparedStatement insertPreparedStatement = null;
        try
        {
            deletePreparedStatement = conn.prepareStatement(sqlDelete);
            deletePreparedStatement.setInt(1, someId);
            deletePreparedStatement.executeUpdate();

            insertPreparedStatement = conn.prepareStatement(sqlInsert);
            for(SomeObject obj : objects)
            {
                insertPreparedStatement.setInt(1, obj.getId());
            }

            insertPreparedStatement.executeBatch();
            // committing transaction
            conn.commit();
            transactionComplete = true;
        }

And I would like 2 prepared statements to be part of one JDBC transaction. I am wondering whether order at which they are created will be the execution order of SQL statements: delete first and inserts - after.

It is he order they are executed, i.e., when executeXXX() is called — OldProgrammer, Sep 17 '13 at 21:08

score 4 · Accepted Answer · answered Sep 17 '13 at 21:39

4

They are executed from top to bottom, so in the order you did it, the deletes will execute first and the insert after them.

answered Sep 17 '13 at 21:39

frank18cr

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JDBC transaction, execution order of sql statements

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