Global variable not working in php

Question

I am facing some errors with use of global variables. I defined a $var in global scope and trying to use it in functions but it not accessible there. Please see below code for better explanation:

File a.php:

<?php

  $tmp = "testing";

  function testFunction(){
     global $tmp;
     echo($tmp);
  }

So a bit about how this function is called.

File b.php:

<?php
  include 'a.php'
  class testClass{
    public function testFunctionCall(){
        testFunction();
    }
  }

The above 'b.php' is called using:

$method = new ReflectionMethod($this, $method);
$method->invoke();

Now the desired output is 'testing' but the output received is NULL.

Thanks in advance for any help.

Is this function defined in a class? If yes, declare $temp as static variable and use self::$tmp instead of using it like global variable. — Paritosh Singh, Sep 17 '13 at 11:17
You are using function with "protected" property. use "public" — Ripa Saha, Sep 17 '13 at 11:22
You need to start a new question as your `recently` edited question is completely different from what we all have answered. — Shankar Narayana Damodaran, Sep 17 '13 at 13:43
@ShankarDamodaran: Sure will do that. Sorry for the question not being formulated properly in the 1st place. — spuri, Sep 19 '13 at 11:44
@ShankarDamodaran: So it stackoverflow wont let me start a new question saying it is a repeated question. So could you help me out with this. I have done a work around but i still dont understand why it wont work. — spuri, Sep 19 '13 at 11:46

Shankar Narayana Damodaran · Accepted Answer · 2013-09-17T11:42:28.373

4

You missed calling your function and also remove the protected keyword.

Try this way

<?php

  $tmp = "testing";

  testFunction(); // you missed this

  function testFunction(){  //removed protected
     global $tmp;
     echo($tmp);
  }

Same code but using $GLOBALS, gets you the same output.

<?php

$tmp = "testing";

testFunction(); // you missed this

function testFunction(){  //removed protected
    echo $GLOBALS['tmp'];
}

edited Sep 17 '13 at 11:42

answered Sep 17 '13 at 11:19

Shankar Narayana Damodaran

68,075
43
96
126

Already tried this. It is working fine in 5.3.x but causing issues in 5.4.10 – spuri Sep 17 '13 at 11:34
@shanilpuri, Can you try the edited answer with `$GLOBALS` on your 5.4.10 ? – Shankar Narayana Damodaran Sep 17 '13 at 11:42
1

Tried using $GLOBALS also. Still the same NULL output. – spuri Sep 17 '13 at 11:46

score 1 · Answer 2 · answered Sep 17 '13 at 11:20

1

This protected function can't access the variable. So use by removing protected.

<?php

  $tmp = "testing";

   function testFunction(){
     global $tmp;
     echo ($tmp);
  }

answered Sep 17 '13 at 11:20

Anshad Vattapoyil

23,145
18
84
132

@ParitoshSingh: yes that was put in the question by mistake. – spuri Sep 17 '13 at 12:41

Johan · Answer 3 · 2013-09-17T11:34:07.227

0

protected functions need to be in a class like this:

 Class SomeClass extends SomeotherClass {

   public static $tmp = "testing";

   protected function testFunction() {

      echo self::$tmp;

   }
}

edited Sep 17 '13 at 11:34

answered Sep 17 '13 at 11:24

Johan

13
2

score 0 · Answer 4 · answered Mar 04 '20 at 10:01

0

I was having the same problem here. As $GLOBALS is seen within any function I used this :

<?php

  $GLOBALS['tmp'] = "testing";

  function testFunction(){

     echo( $GLOBALS['tmp'] );
  }

answered Mar 04 '20 at 10:01

Cyril

1

Global variable not working in php

4 Answers4