Regex replacement issue: using group

Question

I need to replace hundreds of if (ereg("avion","$keyw")) by if (preg_match("@avion@","$keyw")) {

I tried this:

1st : ereg\("(.*)"

2nd : preg_match\("@$1@"

But it replaces the first group by '$1'... Any idea please?

php, but here I try to use ultraedit editor which permit regex expressions... Or use sed in bash perhaps... — user2670167, Sep 17 '13 at 09:59

Ander2 · Answer 1 · 2013-09-17T10:20:22.930

0

Using sed you can try this way:

sed -i".bak" 's/(ereg("\([a-z]*\)","\$keyw"))/\(preg_match\("@\1@","$keyw"\)\)/' filename

EDIT: Updated to match any word, not only 'avion'

edited Sep 17 '13 at 10:20

answered Sep 17 '13 at 10:01

Ander2

Thx but I need a global regex, not just for "avion", I have hundreds of expressions like this... – user2670167 Sep 17 '13 at 10:04
Ok, filename can be *.php? – user2670167 Sep 17 '13 at 10:43
Ok, it works but I have some lines with `ereg("internet, internets"` which are not replaced... – user2670167 Sep 17 '13 at 10:52

Jerry · Accepted Answer · 2013-09-17T11:06:29.227

0

This is working on the UltraEdit version I have:

enter image description here

I'm just not sure why you have @ in your replace.

You can pick "Current file" for all instead of the "Selected Text" I used for the comparison.

Another thing to note, it might be safer to use:

ereg\("(.*?)",

Replace:

preg_match("@$1@",

edited Sep 17 '13 at 11:06

answered Sep 17 '13 at 10:08

Jerry

Oh, yes, you're right, I just choose "UNIX" instead of "Pearl"... Thanks – user2670167 Sep 17 '13 at 10:55
Missing delimiters (I choose @, but it can be /), and it only put the 1st delimiter not the second! – user2670167 Sep 17 '13 at 10:57
Work with `ereg\("(.*)",` and `preg_match\("/$1/",` – user2670167 Sep 17 '13 at 10:59
@user2670167 Ooh, you mean putting the delimiters in the preg_match, sorry you're right there :) – Jerry Sep 17 '13 at 11:03

2 Answers2