How can I suppress command output when using backticks?

Question

Is there a way to supress the command output for git if I use backticks in my shell script? Here is my current code:

OUT=$(git status > /dev/null)

Thanks :)

What do you want to capture in `OUT`? – lurker Sep 13 '13 at 14:46 — lurker, Sep 13 '13 at 14:46

score 7 · Accepted Answer · answered Sep 13 '13 at 13:24

7

I think what you're wanting is to suppress the stderr but not the stdout since you still want the value. You could do this instead:

OUT=$(git status 2>/dev/null)

answered Sep 13 '13 at 13:24

konsolebox

lurker · Answer 2 · 2013-09-13T14:45:59.280

1

In case some output is going to standard error:

OUT=$(git status > /dev/null 2>&1; echo $?)

Of course, this does leave open the question: what is it you want to capture in OUT?

[EDIT] The above will put the return code of git into $OUT.

edited Sep 13 '13 at 14:45

answered Sep 13 '13 at 13:21

lurker

1

Then what do you want to capture in `OUT`? This makes the backticks pointless. – tripleee Sep 13 '13 at 13:41
@tripleee that's a question for the OP – lurker Sep 13 '13 at 13:54

2 Answers2