Execute a script in my zshrc?

Question

S want to execute a script in zshrc and write the output in a variable

VAR=$( /path/to/tool/tool -parameter)

is this possible in zsh?

I don't understand what you mean by "parameters won't work". The code you posted above is fine in terms of syntax. — chepner, Sep 06 '13 at 12:31

score 2 · Answer 1 · answered Sep 05 '13 at 14:07

2

Yes, command substitution works in zsh just like other POSIX shells. See this section of the documentation.

answered Sep 05 '13 at 14:07

Barmar

1 Answers1