I'm trying to find a way to count the number of occurrences of letters in a text file than display them in greatest to lowest depending upon there frequency. This is what I have so far, please help get over this brain block.
def me():
info= input("what file would you like to select?")
filehandle= open(info,"r")
data=filehandle.read()
case = data.upper()
s=('ABCDEFGHIJKLMNOPQRSTUVWXYZ')
for i in range(26):
print(s[i],case.count(s[i]))
me()
Python has a nice built-in class for this: collections.Counter.
In [8]: from collections import Counter
In [9]: with open('Makefile', 'r') as f:
...: raw = Counter(f.read())
...:
In [10]: raw
Out[10]: Counter({' ': 61, 'e': 46, 'p': 38, 'a': 29, '\n': 27, 'c': 27, 'n': 27, 'l': 26, 'd': 25, '-': 22, 's': 22, 'y': 22, 't': 20, 'i': 18, 'o': 18, 'r': 17, '.': 16, 'u': 13, '\t': 12, 'm': 12, 'b': 11, 'x': 10, 'h': 9, '/': 8, ':': 8, '_': 7, "'": 6, ';': 5, '\\': 5, 'f': 5, '*': 3, 'v': 3, '{': 3, '}': 3, 'k': 2, 'H': 1, 'O': 1, 'N': 1, 'P': 1, 'Y': 1, 'g': 1})
This is from the pandas library's Makefile, BTW. To sort them by their frequency in descending order, do:
In [22]: raw.most_common()
Out[22]:
[(' ', 61),
('e', 46),
('p', 38),
('a', 29),
('\n', 27),
('c', 27),
('n', 27),
('l', 26),
('d', 25),
('-', 22),
('s', 22),
('y', 22),
('t', 20),
('i', 18),
('o', 18),
('r', 17),
('.', 16),
('u', 13),
('\t', 12),
('m', 12),
('b', 11),
('x', 10),
('h', 9),
('/', 8),
(':', 8),
('_', 7),
("'", 6),
(';', 5),
('\\', 5),
('f', 5),
('*', 3),
('v', 3),
('{', 3),
('}', 3),
('k', 2),
('H', 1),
('O', 1),
('N', 1),
('P', 1),
('Y', 1),
('g', 1)]
I'm purposefully not using your exact data so that you can try and adapt my solution to your problem.
This is exactly what collections.Counter and its most_common() method are for:
import collections
import string
def me():
info = input("what file would you like to select? ")
filehandle = open(info, "r")
data = filehandle.read().upper()
char_counter = collections.Counter(data)
for char, count in char_counter.most_common():
if char in string.ascii_uppercase:
print(char, count)
me()
A Counter is a dictionary that counts the number of occurrences of different items (in this case, characters). char_counter.most_common() gives us all pairs of characters and counts in sorted order.
We're only interested in letters, so we check if the character is in string.ascii_uppercase. This is simply a string of letters from A to Z.
This looks like a homework very very... much. And I wish you are properly using this website. However, glad you come to the right place and I would try to help you out at least this time.
>>> from collections import defaultdict
>>> d = defaultdict(int)
>>> input_txt = "Now you are just somebody that I used to know"
>>> for letter in input_txt:
... d[letter] += 1
...
>>> import operator
>>> sorted_d = sorted(d.iteritems(), key=operator.itemgetter(1), reverse=True)
>>> sorted_d
[(' ', 9), ('o', 6), ('t', 4), ('e', 3), ('s', 3), ('u', 3), ('a', 2), ('d', 2), ('w', 2), ('y', 2), ('b', 1), ('I', 1), ('h', 1), ('k', 1), ('j', 1), ('m', 1), ('N', 1), ('r', 1), ('n', 1)]
You could do something along these lines:
d={}
with open('/usr/share/dict/words') as f:
for line in f:
for word in line.split():
word=word.strip()
for c in word:
d[c]=d.setdefault(c,0)+1
for k, v in sorted(d.items(), key=lambda t: t[1], reverse=True):
print k,v
For the standard Unix words file, prints:
e 234413
i 200536
a 196995
o 170062
r 160269
...
Y 139
X 92
Q 77
- 2
Others have already given you better solutions using itertools.Counter, but your code was close; you just can't print the sorted output on the fly. You could save the counts in a list, sort it and then print:
def me():
info = input("what file would you like to select?")
filehandle = open(info,"r")
data = filehandle.read()
case = data.upper()
s = ('ABCDEFGHIJKLMNOPQRSTUVWXYZ')
result = []
for i in range(26):
result.append((s[i], case.count(s[i])))
return result
result = me()
for letter, count in sorted(result, key=lambda x: x[1], reverse=True):
print(letter, count)
Still using your logic, you can make the function more readable:
import string
def me():
info = input("what file would you like to select?")
filehandle = open(info,"r")
data = filehandle.read()
case = data.upper()
result = []
for letter in string.uppercase:
result.append((letter, case.count(letter)))
return result
