Slice string into letters

Question

How to slice one string in Go language into array of string letters it contains?

For example, turn string "abc" into array "a", "b", "c".

Answer 1

Use a conversion to runes, for example

package main

import "fmt"

func main() {
        s := "Hello, 世界"
        for i, r := range s {
                fmt.Printf("i%d r %c\n", i, r)
        }
        fmt.Println("----")
        a := []rune(s)
        for i, r := range a {
                fmt.Printf("i%d r %c\n", i, r)
        }
}

Playground

---

Output:

i0 r H
i1 r e
i2 r l
i3 r l
i4 r o
i5 r ,
i6 r  
i7 r 世
i10 r 界
----
i0 r H
i1 r e
i2 r l
i3 r l
i4 r o
i5 r ,
i6 r  
i7 r 世
i8 r 界

---

From the link:

Converting a value of a string type to a slice of runes type yields a slice containing the individual Unicode code points of the string. If the string is empty, the result is []rune(nil).

Answer 2

Use strings.Split on it:

package main

import (
    "fmt"
    "strings"
)

func main() {
    fmt.Printf("%#v\n",strings.Split("abc", ""))
}

http://play.golang.org/p/1tNfu0iyHS

Answer 3

I think Split is what you're looking for:

func Split(s, sep string) []string

If sep is an empty string, it will split the string into single characters:

Split slices s into all substrings separated by sep and returns a slice of the substrings between those separators. If sep is empty, Split splits after each UTF-8 sequence. It is equivalent to SplitN with a count of -1.

Answer 4

The easiest way is to split.

var userString = "some string to split"

newArr:= strings.Split(userString, "")       // split on each char 

fmt.Println(newArr[2])                       // will print "m"