5

I have a number of objects I would like to paginate using Kaminari. However, on the first page I would also like to show a notification allowing the viewer to create his own object, reducing the number of objects that can be displayed on that page. However, the indicated number of pages should also take into account that this first page contains less elements.

Let's say the objects are the letters a through z. The first page should only 4 display letters: {a,b,c,d}, while all other pages should show 6 letters: {e,f,g,h,i,j}, {k,l,m,n,o,p}, etc...

I've been looking at the padding and offset functions, but I have not yet been able to produce the wanted results with these.

@page is the current page

if @page == 1
  Alphabet.page(@page).per(4)
else
  Alphabet.page(@page).per(6).padding(2)
end

=> {a,b,c,d},{i,j,k,l,m,n}, etc...

if @page == 1
  Alphabet.page(@page).per(4)
else
  Alphabet.page(@page).per(6).offset(4)
end

=> {a,b,c,d},{e,f,g,h,i,j}, {e,f,g,h,i,j} etc...
The offset method also does not set the current_page correctly, so this does not seem like the correct method.

How can I get pagination that looks like {a,b,c,d}, {e,f,g,h,i,j}, {k,l,m,n,o,p}, etc..., while also displaying the correct number of pages on the first page, in this case 5?

Pruik
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2 Answers2

2

After some more digging on the internet, I found an interesting segment in 'Kaminari recipes' about paginating arrays, that used Ruby's instance_eval method to manually paginate an array.

I tried using this instance_eval myself, and it seems that this seems to work, although it looks rather hacky

@page = (params[:page] || '1').to_i

if @page == 1
  @alphabet = Alphabet.recent.limit(4)
else
  @alphabet = Alphabet.recent.limit(6).offset(@page*6-8)
end

@alphabet.instance_eval <<-EVAL
  def current_page
    #{@page}
  end
  def total_pages
    ((Alphabet.all.count+2)/6.0).ceil
  end
EVAL

I'm sure there is some better way out there, but since this seems to do the trick for now, I will leave it as is.

Pruik
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1

Buddy, I've found the way of get it working using padding:

@page = (params[:page] || '1').to_i
@per_page = 4
if @page == "1"
  Alphabet.page(@page).per(@per_page - 1)
else
  Alphabet.page(@page).per(@per_page).padding(-1)
end

This way, first page will return 3 items and the other pages 4 items.

Eduardo Ramos
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