PHP Drop Down Box

Question

I have a working drop down box but im not sure how to make it so that if they chose "volksvagen" it would display

"Your Favourite Car is Volksvagen!"

and so on for each of the options, here is the code for the drop down box.

<div id="dropdown">
<?php
$array1 =
array('Volkswagen' , 'Renault' , 'Land Rover');

echo' <select name="cars">';

foreach($array1 as $cars){
        echo'<option value="'.$cars.'">'.$cars.'</option>';
}
echo'</select>';
?>
</div>

You need to wrap that in a `
`, and if you are using the "get" method, just then read `$_GET['cars']`, and if it is non-null, a selection has been made. You'll need a submit button too, of course (if you want something immediately dynamic, then you'll need JavaScript). — halfer, Aug 21 '13 at 11:32
you want to alert "Your Favourite Car is Volksvagen!" upon selection using javascript ? — Prince Singh, Aug 21 '13 at 11:35
i just want to display it on the website, its a task i was given to do with php so i cant use JavaScript — George, Aug 21 '13 at 11:37

chirag ode · Accepted Answer · 2013-08-22T04:13:52.277

1

javascript not used..try it..!!

<form method="post">
<div id="dropdown">
<?php
if(isset($_POST['cars']))
{
$mycar=$_POST['cars'];
}
else
{
$mycar='';
} 
$array1 = array('Volkswagen' , 'Renault' , 'Land Rover');
echo' <select name="cars" onchange="this.form.submit()">';
foreach($array1 as $cars){ ?>
<option value="<?php echo $cars; ?>" <?php if($mycar==$cars) echo "selected='selected'"; ?> ><?php echo $cars; ?></option>
<?php
}
echo'</select>
</div></form>';
echo 'your favourite car is : '; echo $mycar; 
?>

edited Aug 22 '13 at 04:13

answered Aug 21 '13 at 11:44

chirag ode

950
7
15

This didnt work, it just resets to saying "select" in the drop down box whenever something is selected – George Aug 21 '13 at 13:25
i have updated the answer check now.. – chirag ode Aug 22 '13 at 04:08
it doesnt revert to saying select in the box its self anymore however it doesnt echo anything underneath like the "your favourite car is" so on... – George Aug 22 '13 at 10:08
Never mind it is working now – George Aug 22 '13 at 11:20
party..!! accept as answer..click on tick mark given to the left side of my answer – chirag ode Aug 22 '13 at 11:31

score 0 · Answer 2 · answered Aug 21 '13 at 11:39

<div id="dropdown">
<?php
$array1 =
array('Volkswagen' , 'Renault' , 'Land Rover');

echo' <select name="cars" onchange="display_message(this.value);">';

foreach($array1 as $cars){
        echo'<option value="'.$cars.'">'.$cars.'</option>';
}
echo'</select>';
?>
<span id="message"></span>
</div>
<script>
function display_message($selected_value)
{
document.getElementById('message').innerHTML = 'Your Favourite Car is'+$selected_value+'!';
}
</script>

score 0 · Answer 3 · answered Aug 21 '13 at 11:41

<body onload="showCar()">
<div id="dropdown">
<?php
$array1 =
array('Volkswagen' , 'Renault' , 'Land Rover');
echo' <select name="cars" id="cars" onchange="showCar()">';
foreach($array1 as $cars){
        echo'<option value="'.$cars.'">'.$cars.'</option>';
}
echo'</select>';
?>
<div id="demo"> </div>
<script> 
function showCar() {
    var car = document.getElementById('cars').value; 
    document.getElementById("demo").innerHTML="Your Favourite Car is "+car+"!";
}
</script>
</div>  
</body>

Try This

PHP Drop Down Box

3 Answers3