Executing q in shell script

Question

I need to load a q file with a hardcoded dictionary, insert a key and assign returned value from the dictionary to an environment variable inside a shell script.

This how it would look like in q:

q)\l /home/.../marketconfig.q

q)show marketconfig[`US]

This is kind of the form I need it to be in:

CONFIG=\`q /home/.../marketconfig.q ; show marketconfig[\`US]\`

Thanks for help guys!

score 1 · Answer 1 · answered Aug 15 '13 at 16:13

1

test.sh:

#/bin/bash
CONFIG=`q test.q`
echo config is $CONFIG

test.q:

-1 "FOO";
exit 0;

Output:

$ ./test.sh
KDB+ 2.7 2011.11.09 Copyright (C) 1993-2011 Kx Systems
l64/ ...

config is FOO

Seems to work for me. -1 prints on standard out. 0N! works too.

answered Aug 15 '13 at 16:13

Manish Patel

4,411
4
25
48

-1 expects a string, so if your config isn't already a string you'll need to use the string function or -3! – Manish Patel Aug 15 '13 at 16:21

score 1 · Answer 2 · answered Aug 03 '14 at 22:21

1

In bash, you can use a heredoc:

#!/bin/bash
CONFIG=$(q /home/.../marketconfig.q << 'EOF'
show marketconfig[`US]
EOF
)

answered Aug 03 '14 at 22:21

user20349

509
2
9

jump3r · Answer 3 · 2014-08-21T20:04:22.917

0

This is a nice way to express it as one statement without a need to alter original file or add an extra file:

CONFIG=\`q<<<'system "l marketconfig.q"; show marketconfig[\\`US]'`

edited Aug 21 '14 at 20:04

answered Aug 19 '13 at 14:59

jump3r

161
1
7

Executing q in shell script

3 Answers3