Executing a script within a script but continuing on error(s) and saving them to file

Question

If I was to have the following bit of code:

try: 
    execfile("script.py")
except ## unsure what exception goes here...
    continue:
try: 
    execfile("other.py")
except ## unsure what exception goes here...
    continue:

How do I catch all errors from script.py save it to file and then continue onto the next called script

Anyone have any ideas or clues?

replace "continue" with some code that writes an error on a file? — Giwrgos Tsopanoglou, Aug 13 '13 at 00:07
@GiwrgosTsopanoglou I was unsure how to do that part, the catching of the error is where I was stuck. Really simple things can sometimes be too obvious as was the case here. — Ryflex, Aug 13 '13 at 00:13
Yeah, I know what you mean. I think the answer rogaos gave, got you unstuck :) — Giwrgos Tsopanoglou, Aug 13 '13 at 00:27

score 2 · Accepted Answer · answered Aug 13 '13 at 00:05

2

errors = open('errors.txt', 'w')
try: 
    execfile("script.py")
except Exception as e:
    errors.write(e)
try: 
    execfile("other.py")
except Exception as e:
     errors.write(e)
errors.close()

answered Aug 13 '13 at 00:05

vroomfondel

3,056
1
21
32

Hmm, that's easier than I expected. Thank you ever so much, upvote and accepted your answer :) – Ryflex Aug 13 '13 at 00:11

score 1 · Answer 2 · answered Aug 13 '13 at 00:10

1

import traceback # This module provides a standard interface to extract, 
                 # format and print stack traces of Python programs.

try: 
    execfile("script.py")
except:
    traceback.print_exc(file=open('script.traceback.txt', 'w')) # Writing exception with traceback to file script.traceback.txt

# Here is the code that will work regardless of the success of running a script.py

answered Aug 13 '13 at 00:10

mingaleg

2,017
16
28

Interesting method of doing it, I'll use that aswell as rogoas's version. – Ryflex Aug 13 '13 at 00:12

Executing a script within a script but continuing on error(s) and saving them to file

2 Answers2