In Mechanize, how to set the x,y value of ImageButton?

Question

I am using Mechanize Python as the web client to submit a form. However, I did not find a way to set the x,y of ImageButton in this form.

I have tried different ways:

1) the first is to find the control:

bt = frm.find_control('ImageButtonID')
bt.x = 88
bt.y = 10

2) the second one is to use a dictionary:

ctls = {}
ctls['ImageButton1.x'] = 88
ctls['ImageButton1.y'] = 10
data = urllib.urlencode(ctls)
br.open(url,data)

But none of the ways works, Is there any solution? thanks a lot

Here is the html code:

TITLE function EnterTo(){ if (window.event.keyCode == 13){ form1.submit(); } } function ChangeImage() { document.getElementById("yzm").src = document.getElementById("yzm").src+'?'; }

<input name="deptID" type="hidden" id="deptID" value="1" /> <input name="dateType" type="hidden" id="dateType" value="Today" />
<input name="timeType" type="hidden" id="timeType" value="AM" />

<div class="numberBG">
<div class="Repeater">
    <table class="Item">

    <tr>
        <td>
                                    <input type="image" name="Repeater1$ctl00$ImageButton1" id="Repeater1_ctl00_ImageButton1" title="XXXXXXXX" src="images/1_1.jpg" style="border-width:0px;" />
        </td>
    </tr>
</table>        
<table class="table">
    <tr>
        <td style="width:100px;" class="txt">the code</td>
        <td style="width:90px;"><input name="Txt_Yzm" type="text" id="Txt_Yzm" onkeydown="if(event.keyCode==13)event.keyCode=9 " style="width:90px;" />
        <td style="width:50px;"><img src="../../gif.aspx?" id="yzm" onclick="ChangeImage();" alt="try again" style="width:50px;height:24px"></td>
        </tr>
    <tr>
    <td colSpan="3" style="width:240px;"><select name="DropDownList1" id="DropDownList1" style="width:240px;">

From the Chrome, I find the post data is

__VIEWSTATE=%2FwEPDwUJMjE0NzU0MTk4D2QWAmYPZBYIAgMPDxYCHgRUZXh0BQnotKLliqHpg6hkZAIEDw8WAh8ABRfnlKjmiLfvvJo1NTczL%2BWImOWtpuS6rmRkAgUPFgIeC18hSXRlbUNvdW50AgQWCGYPZBYEAgEPDxYCHwAFLOWFseWPluWPt1s3NV3lvZPliY3lj7dbMTAyMF3nrYnlvoXkurrmlbBbNTVdZGQCAw8PFgYeD0NvbW1hbmRBcmd1bWVudAUBMR4ISW1hZ2VVcmwFDmltYWdlcy8xXzEuanBnHgdUb29sVGlwBRLnu7zlkIjmiqXplIDkuJrliqFkZAIBD2QWBAIBDw8WAh8ABSrlhbHlj5blj7dbMV3lvZPliY3lj7dbMjAwMV3nrYnlvoXkurrmlbBbMV1kZAIDDw8WBh8CBQEyHwMFDmltYWdlcy8xXzIuanBnHwQFDOW8gOelqOS4muWKoWRkAgIPZBYEAgEPDxYCHwAFKuWFseWPluWPt1sxXeW9k%2BWJjeWPt1szMDAxXeetieW%2BheS6uuaVsFswXWRkAgMPDxYGHwIFATMfAwUOaW1hZ2VzLzFfMy5qcGcfBAUS5Z%2B65bu65oql6ZSA5Lia5YqhZGQCAw9kFgQCAQ8PFgIfAAUr5YWx5Y%2BW5Y%2B3WzE1XeW9k%2BWJjeWPt1s0MDEzXeetieW%2BheS6uuaVsFsyXWRkAgMPDxYGHwIFATQfAwUOaW1hZ2VzLzFfNC5qcGcfBAUV5YCf5qy%2B44CB6Jaq6YWs5Yqz5YqhZGQCBw8QZBAVABUAFCsDAGRkGAEFHl9fQ29udHJvbHNSZXF1aXJlUG9zdEJhY2tLZXlfXxYGBRxSZXBlYXRlcjEkY3RsMDAkSW1hZ2VCdXR0b24xBRxSZXBlYXRlcjEkY3RsMDEkSW1hZ2VCdXR0b24xBRxSZXBlYXRlcjEkY3RsMDIkSW1hZ2VCdXR0b24xBRxSZXBlYXRlcjEkY3RsMDMkSW1hZ2VCdXR0b24xBQtQcmludEJ1dHRvbgUKQmFja0J1dHRvbpwJ7xuebnfVXIs68Z0mpioF3Dpy&Repeater1%24ctl00%24ImageButton1.x=74&Repeater1%24ctl00%24ImageButton1.y=19&Txt_Yzm=&__EVENTVALIDATION=%2FwEWCwLc%2Bdl4AqPSn9wLAuqo1NQIAq3v2K8JAtW984UHAtDAyPwJAuP1ziAC3oKsnQsC5NXi8AQCw9v50gkCz6%2BuzAH2E8Hvp9iYVUtn77jo3FKnheOfhg%3D%3D

What is `x` and `y`? Show the HTML that you want to scrap or edit and the output that you need — 4d4c, Aug 13 '13 at 11:41
Just a quick note - next time you post any additions to your question try to do it by editing the question and not adding it to comments — 4d4c, Aug 13 '13 at 12:22

score 0 · Answer 1 · answered Aug 13 '13 at 12:32

0

From the look of the HTML mechanize can't handle submitting of this form. As you already know which data to post try to do it manually by using urllib and urllib2 to post data:

import urllib
import urllib2
url = 'http://example.com'
form_data = {'field1': 'value1', 'field2': 'value2'}
params = urllib.urlencode(form_data)
response = urllib2.urlopen(url, params)
data = response.read()

answered Aug 13 '13 at 12:32

4d4c

8,049
4
24
29

Then you are posting some incorect data which server can't handle – 4d4c Aug 13 '13 at 12:47
An error from "System.Web.UI.ClientScriptManager.ValidateEvent(String uniqueId, String argument) +2080236" – xueliang liu Aug 13 '13 at 12:48

score 0 · Answer 2 · answered Aug 14 '13 at 09:42

I find the reason of HTTP error in my problem. Since in python urllib, the "keep-alive" feature is not supported, and the obtained cookie is not valid in the following interaction. I use the cookie obtained in IE to run the code, and get the desired result!

By the way, Fiddler is an amazing Tool to debug HTTP request.

In Mechanize, how to set the x,y value of ImageButton?

2 Answers2