How to use "tr" to replace a digit in a number

Question

My input file contains some series of commands for a number for eg.

13287
13288
13289

I want the following output in all the file.

13281
13282
13283

I am using the following command saved in a script file as I pass the first four digits as argument in the script file.

#!/bin/bash
cat $1_final.txt | tr "$17" "$11" > $1.tmp

Instead of the desired output I am getting the following output. I have checked again the argument passed it 1328 else it will not be able to get the file because the file in the directory is 1328_final.txt

Where I am doing this wrong?

no, Sorry for any confusions.. the file has these numbers all over the place.There are not consecutively placed as shown here. — Mohit Kumar, Aug 10 '13 at 18:57

score 1 · Answer 1 · answered Aug 10 '13 at 17:11

the first argument to tr is a set of characters which will be globally replaced by the corresponding letter from the 2nd arg, another set of characters.

To subtract 6 from each line can be accomplished in many ways:

while read num; do echo $((num-6)); done < file
awk '{print $1 - 6}' file
sed 's/$/ - 6/' file | bc
sed 's/$/ 6 - p/' file | dc

How to use "tr" to replace a digit in a number

1 Answers1